There isn't any. You just have to go through the process and finding out which elements aren't balanced.
Answer:
7.8 × 10∧-4 nm³
Explanation:
Given data:
volume = 7.8x10^-31 m^3
volume in nm³= ?
Solution:
I m³ = 1 × 10∧27
7.8 x 10^-31 × 1 × 10∧27 = 7.8 × 10∧-4 nm³
Answer:
ΔG°′ = 1.737 KJ/mol
Explanation:
The reaction involves the transfer of two electrons in the form of hydride ions from reduced coenzyme Q, CoQH₂ to fumarae to form succinate and oxidized coenzyme Q, CoQ.
The overall equation of reaction is as follows:
fumarate²⁻ + CoQH₂ ↽⇀ succinate²⁻ + CoQ ; ΔE∘′=−0.009 V
Using the equation for standard free energy change; ΔG°′ = −nFΔE°′
where n = 2; F = 96.5 KJ.V⁻¹.mol⁻¹; ΔE°′ = 0.009 V
ΔG°′ = - 2 * 96.5 KJ.V⁻¹.mol⁻¹ * 0.009 V
ΔG°′ = 1.737 KJ/mol
Answer:
The sum would be 69109.4944 ml if that's what you were asking
Molar mass
Ca₃(PO₄)₂ = 310 g/mol
1 mole -------------------> 310 g
2.3x10⁻⁴ mole ---------> ?
m = 2.3x10⁻⁴ * 310 / 1
m = 0.0713 g
hope this helps!
