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krek1111 [17]
3 years ago
6

PI3Cl2 is a nonpolar molecule. Based on this information, determine the I−P−I bond angle, the Cl−P−Cl bond angle, and the I−P−Cl

bond angle. Enter the number of degrees of the I−P−I, Cl−P−Cl, and I−P−Cl bond angles, separated by commas
So I drew it out and am assuming I is the equatorial so I-P-I has a bond angle of 120. Cl is the axial so Cl-P-Cl is 180. So is I-P-Cl 90?
Chemistry
1 answer:
alexdok [17]3 years ago
3 0

Answer: Yes I-P-Cl = 90

Explanation:

This is because the angle formed between I-P-Cl is perpendicular hence the angle is 90°

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Answer is B.

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Explanation:

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Comparing mitosis and meiosis can you help anyone
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5 0
3 years ago
Which chemical reaction is a single replacement reaction? A. Ba(ClO3)2 —> BaCl2 + 3O2 B. 2Mg + O2 —> 2MgO C. Zn + CuCl2 —&
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8 0
3 years ago
Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo
Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

CH_4+2O_2\rightarrow CO_2+2H_2O

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

left\ over=0g

Regards.

7 0
3 years ago
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