Answer:
The coefficient of static friction between the puppy and the floor is 0.7273.
Explanation:
The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:
Where 
is the static friction force, 
is the coefficient of static friction and 
is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore, 
, to make the puppy moving we need to use a force of 80 N, therefore, 
, so we can solve for the coefficient as shown below:
The coefficient of static friction between the puppy and the floor is 0.7273.
holding it and slowly moving forward 2.0m
Answer:
explained
Explanation:
the Neptune was the first planet discovered through the use of mathematics by two astronomers one French and other English. This was breakthrough success in the field of astronomy that marked the importance of mathematics in astronomy. The discovery of the Neptune resulted from the need to explain the motion of Uranus, motion of which could not be explained by the gravitational effect of Jupiter and Neptune.It needed very complex mathematical equations to be Solved to explain it. The two astronomers were Joseph le Verrier and John Couch Adams.
Answer:
k = 1 700.7 N/m
v0 = 9.8 m/s^2
Explanation:
Hello!
We can answer this question using conservation of energy.
The potential energy of the spring (PS) will transform to kinetic energy (KE) of the ball, and eventually, when the velocity of the ball is zero, all that energy will be potential gravitational (PG) energy.
When the kinetic energy of the ball is zero, that is, when it has reached its maximum heigh, all the potential energy of the spring will be equal to the potential energy of the gravitational field.
PS = (1/2) k x^2 <em>where x is the compresion or elongation of the spring</em>
PG = mgh
a)
Since energy must be conserved and we are neglecting any energy loss:
PS = PG
Solving for k
k = (2mgh)/(x^2) = ( 2 * 1.7 * 9.81 * 4.9 Nm)/(0.31^2 m^2)
k = 1 700.7 N/m
b)
Since the potential energy of the spring transfors to kinetic energy of the ball we have that:
PS = KE
that is:
(1/2) k x^2 = (1/2) m v0^2
Solving for v0
v0 = x √(k/m) = (0.31 m ) √( 1 700.7 N/m / 1.7kg)
v0 = 9.8 m/s^2
