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Pani-rosa [81]
3 years ago
14

Dana is on a train traveling at a speed of 20 km/h. Dana walks from the front of the train to the back of the train at a speed o

f 4 km/h. What is Dana’s speed relative to the ground?
Physics
1 answer:
Maslowich3 years ago
7 0

Answer:

16km/h

Explanation:

Vt=20km/h ---train speed

Vd=4km/h

Donas speed relative to ground is:

Vrd=Vt-Vd

Donas is moving in opposite direction of train .

Vrd=20km/h-4km/h

Vrd=16km/h

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Oksana_A [137]

Answer:

 t = 1.62 h

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          θ_i = θ_r

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         tan θ₁ = x₁ / L

         tan θ₁ = \frac{3.56}{1.87}

         θ₁ = tan⁻¹  1.90

         θ₁ = 62.29º

for the second case x₂ = 1.46 m

        tan θ₂ = x₂ / L

        θ₂ = tan⁻¹  \frac{1.46}{1.87}

        θ₂ = 37.98º

the difference in degree traveled is

         Δθ = θ₁- θ₂

          Δθ = 62.29 - 37.98

          Δθ = 24.31º

as in the exercise they indicate that every 15º there is an hour

         t = 24.31º (1h / 15º)

         t = 1.62 h

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3 years ago
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Answer:

Explanation:

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