When the tractor pulls, the boy moves. When the elephant moves, the boy moves. If the elephant moves and has more power than the tractor, the tractor and the boy moves. If the tractor moves and has more power than the elephant, then the elephant and the boy moves. I hope this helps you, have a great day!
The value of the final speed depends on the mass of the ore.
Let's call m the mass of the ore. We can solve the exercise by requiring the conservation of momentum, which must be the same before and after the ore is loaded.
Initially, there is only the cart, so the momentum is

After the ore is loaded, the new mass will be (1200 kg+m), and the new speed is

. The momentum p is conserved, so it is still 12960 kg m/s. Therefore, we have

and so the final speed is
Answer:
a

b

c
Explanation:
From the question we are told that
The Young modulus is 
The length is 
The area is 
Generally the force acting on the tibia is mathematically represented as
derived from young modulus equation
Now this force can also be mathematically represented as
So

substituting values


Since the tibia support half the weight then the force experienced by the tibia is

From the above equation the extension (compression) is mathematically represented as
substituting values


From the above equation the maximum force is
Galileo only saw the system through a scope
Answer:
Explanation:
We shall apply the formula for velocity in case of elastic collision which is given below
v₁ = (m₁ - m₂)u₁ / (m₁ + m₂) + 2m₂u₂ / (m₁ + m₂)
m₁ and u₁ is mass and velocity of first object , m₂ and u₂ is mass and velocity of second object before collision and v₁ is velocity of first velocity after collision.
Here u₁ = 22 cm /s , u₂ = - 14 cm /s . m₁ = 7.7 gm , m₂ = 18 gm
v₁ = ( 7.7 - 18 ) x 22 / ( 7.7 + 18 ) + 2 x 18 x - 14 / ( 7.7 + 18 )
= - 8.817 - 19.6
= - 28.4 cm / s