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Korolek [52]
3 years ago
13

Calcium has a charge of +2. The chart lists the charges of different ions.

Physics
2 answers:
vazorg [7]3 years ago
8 0

Answer: CaO, CaF_2, or CaCl_2

Explanation:- For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here calcium metal is having an oxidation state of +2, thus the anions must  bear a negative charge to form neutral ionic compound.

Thus the possibilities are:

Ca^{2+}+O^{2-}\rightarrow CaO

Ca^{2+}+P^{3-}\rightarrow Ca_3P_2

Ca^{2+}+Cl^{-}\rightarrow CaCl_2

Ca^{2+}+F^{-}\rightarrow CaF_2

dexar [7]3 years ago
3 0
The possible resulting chemical formulas for an ionic compound with calcium given the respective charges of the ions are: CaO, CaMg, or CaF₂ and CaO, CaF₂, or CaCl₂. This is because when dealing with these compounds, you simply need to interchange the oxidation state of the two elements and place as the subscript of the element. For instance, when we have Ca²⁺ and F⁻, the result is CaF₂. However, when the oxidation states of the two compounds are equal, the subscript is 1. That is, for Ca²⁺ and Mg²⁻, the result is CaMg. And for Ca²⁺ and Cl⁻, the result is CaCl₂. 
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CHALLENGE
luda_lava [24]

When the tractor pulls, the boy moves. When the elephant moves, the boy moves. If the elephant moves and has more power than the tractor, the tractor and the boy moves. If the tractor moves and has more power than the elephant, then the elephant and the boy moves. I hope this helps you, have a great day!

5 0
3 years ago
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A 1200-kg ore cart is rolling at 10.8 m/s across a flat friction-free surface. a crane suddenly drops of ore vertically into the
Andre45 [30]
The value of the final speed depends on the mass of the ore.

Let's call m the mass of the ore. We can solve the exercise by requiring the conservation of momentum, which must be the same before and after the ore is loaded.

Initially, there is only the cart, so the momentum is
p=Mv=(1200 kg)(10.8 m/s)=12960 kg m/s
After the ore is loaded, the new mass will be (1200 kg+m), and the new speed is v_f. The momentum p is conserved, so it is still 12960 kg m/s. Therefore, we have
p=12960 kg m/s =(1200 kg+m)v_f
and so the final speed is
v_f =  \frac{12960 kg m/s}{1200 kg +m}
5 0
3 years ago
The tibia is a lower leg bone (shin bone) in a human. The maximum strain that the tibia can experience before fracturing corresp
IRISSAK [1]

Answer:

a

   k    =  11600000 N/m

b

   \Delta  L  =  3.2323 *10^{-5} \ m

c

  F =  3750.28 \  N  

Explanation:

From the question we are told that

    The Young modulus is  E =  1.4 *10^{10} \  N/m^2

     The length is  L  =  0.35 \ m

      The  area is  2.9 \ cm^2  =  2.9 *10^{-4} \ m ^2

   

Generally the force acting on the tibia is mathematically represented as

       F =  \frac{E *  A  *  \Delta  L }{L}    derived from young modulus equation

Now this force can also be mathematically represented as

      F =  k *  \Delta  L    

So

     k    =  \frac{E *  A  }{L}

substituting values

     k    =  \frac{1.4 *10^{10} *  2.9 *10^{-4}  }{ 0.35}

     k    =  11600000 N/m

    Since the tibia support half the weight then the force experienced by the tibia is  

        F_k  =  \frac{750 }{2}  =  375 \  N

 From the above equation the extension (compression) is mathematically represented as

          \Delta  L  =  \frac{ F_k  *  L  }{ A *  E }        

substituting values

           \Delta  L  =  \frac{  375   *  0.35  }{ (2.9 *10^{-4}) *   1.4*10^{10} }

           \Delta  L  =  3.2323 *10^{-5} \ m

From the above equation the maximum force is  

        F =  \frac{1.4*10^{10} *  (2.9*10^{-4})  *  3.233*10^{-5} }{ 0.35}  

         F =  3750.28 \  N  

4 0
3 years ago
Why did Ptolemy and Galileo had different views about the solar system?
iVinArrow [24]
Galileo only saw the system through a scope
5 0
3 years ago
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Assume: Moving to the right is positive. A(n) 7.7 g object moving to the right at 22 cm/s makes an elastic head-on collision wit
krek1111 [17]

Answer:

Explanation:

We shall apply the formula for velocity in case of elastic collision which is given below

v₁ = (m₁ - m₂)u₁ /  (m₁ +  m₂)  + 2m₂u₂ / (m₁ +  m₂)

m₁ and u₁ is mass and velocity of first object , m₂ and  u₂ is mass and velocity of second object before collision and v₁ is velocity of first velocity after collision.

Here u₁ = 22 cm /s , u₂ = - 14 cm /s . m₁ = 7.7 gm , m₂ = 18 gm

v₁ = ( 7.7 - 18 ) x 22 / ( 7.7 + 18 )  + 2 x 18 x - 14 / ( 7.7 + 18 )

= - 8.817 - 19.6

= - 28.4 cm / s

5 0
3 years ago
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