Answer: 0.70g
The half-life of iron-53 would be 8.51 minutes. So, in 25.53 minutes would be equal to: 25.53 min/ (8.51 minutes/ half-life)= 3 half-life.
Every half-life will reduce the original weight into half. So, the final weight would be:
final weight = original weight * 1/2 ^(time)
final weight = 5.6g * (1/2)^(3 half-life)
final weight = 5.6g * 1/8= 0.7g
That would result in an exothermic reaction.
Hope this helps :)
Metals:
<span>Distinguishing luster (shine)
</span><span>Malleable and ductile (flexible) as solids
</span><span>Conduct heat and electricity
</span><span>Metallic oxides are basic, ionic
</span><span>Cations in aqueous solution
</span>
Nonmetals:
<span>Non-lustrous, various colors
</span><span>Brittle, hard or soft
</span><span>Poor conductors
</span><span>Nonmetallic oxides are acidic, compounds
</span><span>Anions, oxyanions in aqueous solution
</span>
Hey there!:
Temperature in kelvin : 45 + 273 => 318 K
Number of moles H2:
p * V = n * R * T
4.46 * 0.579 = n * 0.082 * 318
2.58234 = n * 26.076
n = 2.58234 / 26.076
n = 0.09903 moles of H2O
Given the reaction:
XeF6(s) + 3 H2(g) → Xe(g) + 6 HF(g)
Molar mass XeF6 = 245.3 g/mol
0.09903 mol H2O * ( 1 mol XeF6 / 3 mol H2 ) * 245.3
= 8.09 g of XeF6
Hope that helps
Ionization energy is the amount of energy required to remove the electron that is most loosely bound of an isolated gaseous atom to form a cation.
Electron affinity is the amount of energy released when an electron is added to a neutral atom or a molecule in a gaseous state to form negation ion.
The difference of ionization energy and electron affinity is ionization energy is the required energy to remove an electron from a neutral atom. Whereas, electron affinity is the energy change when a neutral atom attracts an electron to become a negative ion.