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ipn [44]
3 years ago
11

When John bought his new computer, he purchased an online computer help service. The help service has a yearly fee of $25.50 and

a S10.50 charge for each help session a person uses. If John can only spend S170 for computer help this year, what is the maximum number of help sessions he can use this year?
Mathematics
1 answer:
Westkost [7]3 years ago
7 0
The yearly fee can be subtracted, resulting in 170-25.50=144.5

So with 10.50 a session, you must divide, resulting in around 13.8 sessions.

13 sessions if you need a whole number.

Hope this helps
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find the two angle measures from the diagram 12x-18 8x +10 answers are 114 and 66 or 66 and 66 or 114 and 114 will mark brainies
MArishka [77]

Answer:

<h2>66 and 66</h2>

Step-by-step explanation:

opposite angles are equal

12x - 18 = 8x + 10

combine similar terms:

12x - 8x = 10 + 18

4x = 28

x = 28/4

x = 7

plugin the value of x=7 back into the equation to solve the angle

= 12x - 18

= 12(7) - 18

= 66

= 8x + 10

= 8(7) + 10

= 66

4 0
4 years ago
A single card is drawn from a standard 52-card deck. Let D be the event that the card drawn is a black card and let F be the eve
tester [92]

Answer:

The indicated probability of P(D \cup F')=\frac{25}{26}

Step-by-step explanation:

Probability of an event E to be;

P(E) = \frac{Number of events within E}{Total number of possible outcomes}

As per the given condition:

Total number of possible outcomes =  52 cards.

Let the event be D and F as follows;

D : Drawn card is a black card

F : Drawn card is a 10 card.    

Then,

From the given condition:

P(D) = \frac{26}{52}   [Out of 52 cards, 26 were black] ,

P(F) = \frac{4}{52}    [Out of 52 cards, there are four  10 cards]

For any two events A and B we always have;

P(A \cup B) = P(A)+P(B)-P(A \cap B)

Now, we have to find the indicated probability:

P(D \cup F')=P(D)+P(F')-P(D \cap F')               ......[1]

First find the P(F');

P(F') =1-P(F) = 1-\frac{4}{52} =\frac{52-4}{52} =\frac{48}{52}

Also, to find P(D \cap F').

We use the formula :

For any event A and B independent variable.

P(A \cap B) =P(A) \cdot P(B)

then;

P(D \cap F') =P(D) \cdot P(F') = \frac{26}{52} \cdot \frac{48}{52} =\frac{24}{52}

Now, substitute these in [1];

P(D \cup F')=\frac{26}{52} +\frac{48}{52} -\frac{24}{52}=\frac{26+48-24}{52} =\frac{50}{52} = \frac{25}{26}

Therefore, the probability of P(D \cup F')=\frac{25}{26}



3 0
3 years ago
What sort of information can you get from conditional frequencies that you couldn't get by just looking at the relative frequenc
shepuryov [24]

Answer:

<h2>Conditional frequencies offer more specific information to analyse certain data set.</h2>

Step-by-step explanation:

A conditional frequency is a type of relative frequency which involves a condition to be defined.

For example, the conditional frequency of having a house given that the person is female. Notice that this example shows the condition "being female", so the conditional frequency would be all females who own a house.

On the other hand, the relative frequency is just a ratio between the frequency of the data and the total number of  data. It's doesn't includes a condition to be defined, that's the difference.

Therefore, conditional frequencies offer more specific information to analyse certain data set.

3 0
3 years ago
Would you pls answer this question?
Ilya [14]

Answer:

24÷6= 4

so h= 3×4= 12feet

5 0
3 years ago
Read 2 more answers
A vegetable garden and surrounding path are shaped like a square that together are 10ft wide. The path is 3ft wide. Find the tot
Alina [70]

Answer:

256

Step-by-step explanation:

since the the path surounds both sides of the garden you have to add 2 x instead of just x

let me show you what i mean. 10=garden width and 3=path width=x

since it is a square, we can calculate the area by taking one side and squaring it so you get (10+2x)^2 which is 16^2 since x is 3, the width of the garden

to do simaler problems just use thei formula (garden length+2path length)^2 or (garden length+2path length)times(garden length+2path length)

5 0
3 years ago
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