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Rashid [163]
3 years ago
11

Why are plant cells and animal cells different

Chemistry
1 answer:
Alenkinab [10]3 years ago
5 0
The Plant cell has cell walls to prevent it from basting in case of large amount of water.
while the animal cell doesn't have cell walls.
                 
                                  P.S. PHANTOM SNIPERS
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Predict which of the substances, NH3, N2, CH2Cl2, Cl2, CCl4 has
gulaghasi [49]

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djsjwjwjdjxjdbs djwuqidx8diw d xbd

6 0
3 years ago
What are two things affected by friction
11111nata11111 [884]

Answer:

speed and how slidey things are

Explanation:

4 0
3 years ago
The combustion of one mole of liquid ethanol, CH3CH2OH, produces 1367 kJ of heat. Calculate how much heat is produced when 235.0
deff fn [24]

Answer:- 6984 kJ of heat is produced.

Solution:- From given information, 1367 kJ of heat is produced by the combustion of 1 mole of ethanol. We are asked to calculate the heat produced by the combustion of 235.0 g of ethanol.

Let's convert given grams to moles and multiply by the heat produced by one mole of ethanol to get the total heat produced. Molar mass of ethanol is 46 grams per mole. The set will be:

235.0g(\frac{1mole}{46g})(\frac{1367 kJ}{1mole})

= 6984 kJ

So, 6984 kJ of heat is produced by the combustion of 235.0 g of liquid ethanol.

6 0
4 years ago
An acid solution is 0.100 M in HCl and 0.210 M in H2SO4. What volume of a 0.150 M solution of KOH must be added to 500.0 mL of t
Dmitry_Shevchenko [17]

Answer:

When we add 0.33L of KOH only the HCl solution will be neutralized. When we add <u>1.4 L</u> of KOH, all of the acid (the HCl and H2SO4 solution) will be neutralized.

Explanation:

<u>Step 1:</u> Data given

The solution has 0.100 M HCl and 0.210 M H2SO4

Molarity KOH = 0.150 M

Volume of acid solution = 500 mL = 0.5 L

<u>Step 2: </u>Calculate moles of HCl

Moles HCl = Molarity HCl * volume

Moles HCl = 0.100 M * 0.5 L

Moles HCl = 0.05 moles

<u>Step 3:</u> Calculate moles of H2SO4

Moles H2SO4 = 0.210 M * 0.5 L

Moles H2SO4 = 0.105 moles

<u>Step 4:</u> The balanced neutralization reaction of KOH with HCl can be written as:

KOH + HCl → KCl + H2O

The mole ratio is 1:1

This means to neutralize 0.05 moles HCl, we need 0.05 moles KOH

<u>Step 5:</u> The balanced neutralization reaction of KOH with H2SO4 can be written as:

2KOH + H2SO4 → K2SO4 + 2H2O

The mole ratio KOH: H2SO4 is 2:1

This means to neutralize 0.105 moles H2SO4 we need 0.210 moles KOH

<u>Step 6: </u>Calculate volume of KOH needed to neutralize the solution

To neutralize the HCl solution: 0.05 moles / 0.150 M = 0.33 L KOH needed

To neutralize the H2SO4 solution: 0.210 moles / 0.150 M = 1.4 L KOH needed

When we add 0.33L of KOH the HCl solution will be neutralized. When we add 1.4 L of KOH the HCl and H2SO4 solution will be neutralized.

4 0
3 years ago
1. Where are the most massive elements found on the periodic table?
Setler79 [48]
The answer is A. At the bottom right
4 0
3 years ago
Read 2 more answers
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