Answer:
1.33 M
Explanation:
We'll begin by writing out the data obtained from the question. This includes the following:
Volume of the stock solution (V1) = 0.5L
Molarity of the stock solution (M1) = 4M
Volume of diluted solution (V2) = 1.5L
Molarity of the diluted solution (M2) =.?
With the application of the dilution formula, the molarity of the diluted solution can be obtained as follow:
M1V1 = M2V2
4 x 0.5 = M2 x 1.5
Divide both side by 1.5
M2 = (4 x 0.5) / 1.5
M2 = 1.33 M
Therefore the molarity of the diluted solution is 1.33 M
Answer:
Magnet with a positive and a negative pole
Explanation:
A great analogy to demonstrate what a polar molecule looks like is to imagine a magnet. A magnet has one positively charged end and one negatively charged end, two poles, that is.
Imagine that we have a magnet of a shape of a prism (water molecule has a bent shape). The two base vertices of the face of the triangle are positively charged, that's because hydrogen is less electronegative than oxygen and, hence, the two hydrogen atoms are partially positively charged in a water molecule.
Oxygen is more electronegative than hydrogen meaning it has a greater electron-withdrawing force, so electrons are closer to oxygen within the O-H bonds. Oxygen, as a result, becomes partially negatively charged, so it's our negative pole of the magnet.
Answer:
second option
O=C-OR
R
Explanation:
ester: A compound most often formed by the condensation of an alcohol and an acid, with elimination of water. It contains the functional group C=O. joined via carbon to another oxygen atom.
https://brainly.in/question/21138251
<em>Answer:</em>
<em>Ether:</em>
Ether are organic compounds that contain ether functional group , in which oxygen atom is connected with two alkyl or aryl group.
They have general formula as follow
- R---O---R or R'---O----R or R'---O---R'
while R = Alkyl
R' = Aryl
Answer:
mass of CO₂ = 5.402 g
Explanation:
At STP, 1 mole of any gas takes up 22.4L of volume
Thus, 1 mole = 22.4 L
1 L = 1 mole ÷ 22.4
Therefore, 2.75 L = 2.75 mole ÷ 22.4 = 0.123 moles
Molecular weight of CO₂ = 44 g/mole
mass of CO₂ = molecular weight * number of moles = 44 g/mole * 0.123 moles
mass of CO₂ = 5.402 g