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vagabundo [1.1K]
3 years ago
11

What is the mass of ca(oh)2 in 110. mL of 1.244 M ca(oh)2 solution

Chemistry
1 answer:
stealth61 [152]3 years ago
7 0
<em>V= 110mL = 110cm³ = 0,11dm³</em>
<em>C = 1,244 mol/L = 1,244 mol/dm³</em>


C = n/V
n = 1,244×0,11
<u>n = 0,13684 moles</u>

<em>mCa(OH)₂ = 74 g/mol</em>


1 mole Ca(OH)₂ ------------ 74g
0,13684 ---------------------- X
X = 74×0,13684
<u>X = 10,12616g</u>

:)
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Explanation:

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Therefore, calculate number of moles of Sb as follows.

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           Moles of oxygen = \frac{mass}{\text{molar mass}}

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We multiply both the ratio by 2 in order to get a whole number. Therefore, the ratio will be 2 : 5.

Thus, we can conclude that the empirical formula of the given oxide is Sb_{2}O_{5}.

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