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densk [106]
3 years ago
5

How many formula units are there in 14.50 moles of any compound? ___X 10^___formula units

Chemistry
1 answer:
Nonamiya [84]3 years ago
8 0

Answer:

8.73 × 10²⁴ formula units

Explanation:

To calculate the number of formula units a substance contain, we multiply the number of moles by Avagadro number (6.02 × 10²³)

number of formula units = 14.50 moles × 6.02 × 10²³

= 87.29 × 10²³

= 8.73 × 10²⁴ formula units.

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Answer above should be correct!
5 0
3 years ago
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Magma can partially crystallize at depth and then rise to shallow depths where the remaining magma solidifies. The early-formed
Doss [256]
<h2>Phenocrysts and Porphyritic texture </h2>

Explanation:

  • The early formed crystals are of phenocrysts and the texture of these crystals is porphyritic texture.  
  • This crystallization occurs when early-forming plagioclase crystals which are rich in calcium start coating with plagioclase crystals which are rich in sodium.
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5 0
3 years ago
Fe(s) + 2HCl(aq) --&gt; FeCl2(aq) + H2(g)
soldier1979 [14.2K]

Answer:

In the option(A) moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

Explanation:

Fe(s) + 2HCl(aq)\rightarrow  FeCl_2(aq) + H_2(g)&#10;

Moles of HCl = n

Molarity of HCl = 1.0M

Volume of HCl solution = 30.0 mL = 0.030 L (1 mL = 0.001L)

Moles=Molarity\times Volume (L)

n=1.0M\times 0.030 L=0.030 mol

Moles of Fe = \frac{0.56 g}{56 g/mol}=0.01 mol

According to recation , 1mol of Fe reacts with 2 mol HCl. Then 0.01 mole of Fe will recat with :

\frac{2}{1}\times 0.01 mol= 0.02 mol of HCl

This means that HCl uis in excess , hence excessive reagent.

Moles of HCl left unreacted :

= 0.030 mol - 0.020 mol = 0.010 mol

But in the option moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

8 0
3 years ago
A 700.0 mL gas sample at STP is compressed to a volume of 200.0 mL, and the temperature is increased to 30.0°C. What is the new
dolphi86 [110]

Answer: The new pressure of the gas in Pa is 388462

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas at STP = 10^5Pa

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 700.0 ml

V_2 = final volume of gas = 200.0 ml

T_1 = initial temperature of gas = 273 K

T_2 = final temperature of gas = 30^oC=273+30=303K

Now put all the given values in the above equation, we get:

\frac{10^5\times 700.0ml}{273K}=\frac{P_2\times 200.0ml}{303K}

P_2=388462Pa

The new pressure of the gas in Pa is 388462

6 0
3 years ago
5. If 1 g of a gas occupies a volume of 300 mL at STP, what is the molecular weight of the gas?
ikadub [295]

Answer:

74,67 gr/mol

Explanation:

At STP 1 mole of an ideal gas has volume of 22,4 L. Since we know the volume of the gas we can find the number of moles of the gas. (300 mL=0,3 L)

n=0,3L/22,4 L=0,01339 mol

Since we know weight of the gas as 1 g, we can find the molecular weight as;

MW=1 g/0,01339 mol =74,67 gr/mol

3 0
2 years ago
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