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photoshop1234 [79]
3 years ago
13

What is the formula to find the area of circle​

Chemistry
1 answer:
Advocard [28]3 years ago
6 0

Answer:

A= π * r *2

Explanation:

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_______________________ turns blood to cherry red and produces a patchy, pinkish color in the lividity of the corpse.a. Carbon m
IgorC [24]

Answer: a. Carbon monoxide

Explanation:

The carbon monoxide gas competes with the oxygen in the blood to occupy the binding affinity of the hemoglobin thus the blood changes it's color to cherry red.

In postmortem lividity, the body becomes discolored due to the effect of flow of blood from the interstitial tissues and suspended under the force of gravity. This can be seen on the dependent parts of the body and the position of body after death. The color of the postmortem lividity depends on the color of the hemoglobin.

In case of carbon monoxide poisoning the color of postmortem lividity appears to be cherry red as color of the hemoglobin is cherry red. Thus cherry red or dark pinkish patches appear in the corpse as lividity.

8 0
3 years ago
What do element; atoms; molecule; chemical bond; compound; mixture; and substance have in common
sleet_krkn [62]
They are all things you can do to elements on the periodic table?
7 0
3 years ago
Be sure to answer all parts. Consider the following balanced redox reaction (do not include state of matter in your answers): 2C
timurjin [86]

Answer:

The specie which is oxidized is:- CrO_2^-

The specie which is reduced is:- ClO^-

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

For the given chemical reaction:

2CrO_2^- + 6ClO^- + 2H_2O\rightarrow 2CrO_4^{2-} + 3Cl_2 + 4OH^-

The half cell reactions for the above reaction follows:

Oxidation half reaction:  CrO_2^- + 2H_2O + 4OH^-\rightarrow CrO_4^{2-} + 4H_2O + 3e^-

Reduction half reaction:  2ClO^- + 4H_2O + 2e^-\rightarrow Cl_2 + 2H_2O + 4OH^-

Thus, the specie which is oxidized is:- CrO_2^-

The specie which is reduced is:- ClO^-

8 0
3 years ago
Which of the following has the greatest electronegativity difference between the bonded atoms? a. A strong acid made of hydrogen
NARA [144]

Answer: Option (d) is the correct answer.

Explanation:

Electronegativity value of hydrogen is 2.2.

Electronegativity value of chlorine is 3.16.

Electronegativity value of carbon is 2.55.

Electronegativity value of oxygen is 3.44.

Electronegativity value of nitrogen is 3.04.

Electronegativity value of sodium is 0.93.

Electronegativity value of iodine is 2.66.

Therefore, calculate the electronegativity difference between the bonded atoms as follows.

  • Electronegativity difference of HCl = Electronegativity value of chlorine - electronegativity value of hydrogen

                                                          = 3.16 - 2.2

                                                          = 0.96

  • Electronegativity difference of CO = Electronegativity value of oxygen - electronegativity value of carbon

                                                          =  3.44 - 2.55

                                                          = 0.89

  • Electronegativity difference of N_{2} = Electronegativity value of nitrogen - electronegativity value of nitrogen

                                                           = 3.04 - 3.04

                                                           = 0

  • Electronegativity difference of NaI = Electronegativity value of iodine - electronegativity value of sodium

                                                          = 2.66 - 0.93

                                                          = 1.73

So, we can see that highest electronegativity difference is 1.73 and it is shown by NaI molecule.

Thus, we can conclude that a group 1 alkali metal bonded to iodide, such as NaI has the greatest electronegativity difference between the bonded atoms.

5 0
3 years ago
Read 2 more answers
PLease help!!! Im in the process of taking my final!!!!! HELPPPPP
Katarina [22]

Answer:

The answer to your question is Aluminum

Explanation:

Number of clues

1.- If this element has 3 rings in its Bohr model, we are looking for and element located in the third period of the periodic table.

For example Sodium, Magnesium, Aluminum, Silicate, Phosphorus, Sulfur, Chlorine and, Argon.

2.- It makes three bonds to become stable, then we are looking for and element located in the third group like

 Boron, Aluminum,  Gallium, Indium, etc

Conclusion

The element that has both characteristics is Aluminum

8 0
3 years ago
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