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Olegator [25]
3 years ago
13

Is 4Al + 3O2>Al2O balanced

Chemistry
1 answer:
Goryan [66]3 years ago
5 0

Answer:

no it is not a balanced equation

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How does concentration affect the chemical equilibrium?
nevsk [136]
When the concentration of a reactant is increased, the chemical equilibrium will shift towards the products. More product is formed and the concentration of the reactants decreases as the concentration of the products increases.
7 0
3 years ago
Which of the following is transferred due to a temperature difference?
quester [9]
Water can be turned to ice if to cold gas if to hot 
ice can turn to water if to hot and stay the same if to cold 
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hope this helps 
 
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2 years ago
What type of ecosystem can you find a lion in?
Katena32 [7]

Answer:

A grassland ecosystem

Explanation:

4 0
3 years ago
Read 2 more answers
g If a small amount of a strong acid is added to a buffer made up of a weak acid, HA, and the sodium salt of its conjugate base,
ikadub [295]

Answer:

Explanation is in the answer

Explanation:

The pH of the buffer solution does not change appreciably because the strong acid (free H⁺) reacts with conjugate base of buffer producing more weak acid. pH formula of buffers is (Henderson-Hasselbalch formula):

pH = pKa + log ( [A⁻] / [HA] )

The addition of strong acid decreases [A⁻] increasing [HA]. pH change just in the log of the ratio of [A⁻] with [HA], that is a real little effect over pH of the buffer solution.

5 0
3 years ago
A metal ion Mⁿ⁺ has a single electron. The highest energy line in its emission spectrum occurs at a frequency of 2.961 x 10¹⁶ Hz
Whitepunk [10]

Answer:

z≅3

Atomic number is 3, So ion is Lithium ion (Li^+)

Explanation:

First of all

v=f*λ

In our case v=c

c=f*λ

λ=c/f

where:

c is the speed of light

f is the frequency

\lambda=\frac{3*10^8}{2.961*10^{16}}\\ \lambda=1.01317*10^{-8} m

Using Rydberg's Formula:

\frac{1}{\lambda}=R*z^2*(\frac{1}{n_1^2}-\frac{1}{n_2^2})

Where:

R is Rydberg constant=1.097*10^7

z is atomic Number

For highest Energy:

n_1=1

n_2=∞

\frac{1}{1.01317*10^{-8}}=1.097*10^{7}*z^2*(\frac{1}{1^2}-\frac{1}{\inf})\\z^2=8.99\\z=2.99

z≅3

Atomic number is 3, So ion is Lithium ion (Li^+)

3 0
3 years ago
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