Answer:
CaCl₂ > CH₃OH = LiCl > C₆H₁₂O₆
Explanation:
The osmotic pressure of a compound is calculated using the following expression:
π = MRT (1)
This expression is used when the substance is nonelectrolyte. If the solution is electrolyte solution then we need to count the van't hoff factor into the expression so:
π = MRTi (2)
Now, we have 4 solutions here, only two of them are electrolyte solution, this means that these solutions can be dissociated into separate ions. These solutions are LiCl and CaCl₂. It can be shown in the following reactions:
LiCl -------> Li⁺ + Cl⁻ 2 ions (i = 2)
CaCl₂ ---------> Ca²⁺ + 2Cl⁻ 3 ions (i = 3)
The methanol (CH₃OH) and glucose (C₆H₁₂O₆) are non electrolyte solutions, therefore they are not dissociated. So, let's use expression (1) for methanol and glucose, and expression (2) for the salts:
CaCl₂: π = 1 * 3 * RT = 3RT
CH₃OH: π = 2 * RT = 2RT
C₆H₁₂O₆: π = 1 * RT = 1RT
LiCl: π = 1 * 2 * RT = 2RT
Finally with these results we can conclude that the decreasing order of these solutions according to their osmotic pressures are:
<h2>
CaCl₂ > CH₃OH = LiCl > C₆H₁₂O₆</h2>
Mass of O2 = 4 g, converting to moles = 4 g / 32 g/mol = 0.125 mol
Mass of He = 4 g, converting to moles = 4 g / 4 g/mol = 1 mol
Temperature T = 65 + 273 = 338
Volume of the vessel V = 5 L
Universal Gas constant R = 0.08206 L atm / mol K,Pressure by O2 in vessel P1 = nRT / V = 0.125 x 0.08206 x 338 / 5 = 0.69
atm
Pressure by He in vessel P2 = nRT / V = 1 x 0.08206 x 338 / 5 = 5.55 atmTotal pressure = 0.69 + 5.55 = 6.24 atm
Answer:
Volumen C6H8O6(sln) = 2.569 L ≅ 2.6 L
Explanation:
vitamin C ≡ ascorbic acid (C6H8O6)
∴ vitamin C/daily = 75.0 mg/d
∴ molar mass C6H8O6 = 176.12 g/mol
solution:
∴ <em>C</em> C6H8O6 = 0.002486 mol/L
⇒ ppm C6H8O6 = (0.002486 mol/L)*(176.12 g/mol)*(1000 mg/g)
⇒ ppm C6H8O6 = 437.834 mg/L
for a 15.0 day:
⇒ Volume C6H8O6(sln) = (75.0 mg/d)*(L/437.834 mg)*(15.0 d)
⇒ Volume C6H8O6(sln) = 2.569 L
Answer : At temperatures greater than this reaction is spontaneous under standard conditions.
Explanation : Given,
= 131.3 KJ/mole = 131300 J/mole
= 127.6 J/mole.K
Gibbs–Helmholtz equation is :
As per question the reaction is spontaneous that means the value of is negative or we can say that the value of is less than zero.
The above expression will be:
Now put all the given values in this expression, we get :
Therefore, at temperatures greater than this reaction is spontaneous under standard conditions.