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padilas [110]
3 years ago
5

i'm reasking this, i need help with this and it's due today. the answer isn't 30,240 minutes, it's the blanks i need filled in :

)

Chemistry
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

Explanation:

24hours ×21 days=

you will get the answeer

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What evidence supports the law of conservation of energy?
Travka [436]

Answer:

light energy is converted to chemical energy during photosynthesis.

Explanation:

Law of conservation of energy says: Energy can neither be created nor destroyed-only converted from one form of energy to another.

3 0
3 years ago
What are the [H₃O⁺] and the pH of a buffer that consists of 0.20 M HF and 0.25 M KF (Kₐ of HF = 6.8X10⁻⁴)?
Charra [1.4K]

The pH of 0.20 M HF (Hydrofluoric acid) is 3.27.  Whereas, [H₃O⁺] for the same is 6.8 X10 ⁻⁴

<h3>What is Hydrofluoric acid?</h3>

A hydrogen fluoride and water solution is hydrofluoric acid. HF solutions are colorless, corrosive, and acidic. The majority of fluorine-containing chemicals are made using it; examples include the substance PTFE and the widely used psychiatric drug fluoxetine. Aluminum, plastics, electrical components, pharmaceuticals, high-octane fuel, fluorescent light bulbs, and refrigerants are all made with hydrogen fluoride. The production of refrigerants uses 60% of the hydrogen fluoride used in manufacturing. corrosive due to the acid's H+ ions and poisonous due to the fluoride ions F-, which can penetrate deeply, chelate calcium and magnesium, and thus upset biological balances due to the destruction of the skin's or an eye's outermost layer.

To learn more about Hydrofluoric acid, visit:

brainly.com/question/24194581

#SPJ4

5 0
2 years ago
A 12.0 g sample of a metal is heated to 90.0 ◦C. It is then dropped into 25.0 g of water. The temperature of the water rises fro
deff fn [24]

Answer:

The specific heat of the metal is 0.34 J/g°C

Explanation:

Step 1: Data given

Mass of the metal = 12.0 grams

Mass of the water = 25.0 grams

Initial temperature of the metal = 90.0 °C

Initial temperature of the water = 22.5 °C

Final temperature = 25 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of the metal

Qlost = Qgained

Q = m*c*ΔT

Qmetal = -Qwater

m(metal) *c(metal)* ΔT(metal) = -m(water) * c(water) *ΔT(water)

⇒ with mass of metal = 12.0 grams

⇒ with c(metal) = TO BE DETERMINED

⇒ with ΔT(metal) = T2 - T1  = 25.0°C - 90.0 °C = -65.0 °C

⇒ with mass of water = 25.0 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.0 - 22.5 °C = 2.5 °C

12.0 * c(metal) * -65.0 °C = -25.0g * 4.184 J/g°C * 2.5°C

-780.0 * c(metal) = -2615  ( 2.6*10^3 with sig figs)

c(metal) = 0.335 (=0.34 with sig figs)

The specific heat of the metal is 0.34 J/g°C

3 0
3 years ago
The air pressure in a tire is 2.38 atm. What is the pressure in kilopascals.
Anna71 [15]

Answer:

The answer is

<h2>241.15 kPa</h2>

Explanation:

To find the pressure in kilopascals we must first find the pressure in Pascal

To find the pressure in Pascal we use the conversion

1 atm = 101 , 325 Pa

If 1 atm = 101325 Pa

then 2.38 atm = 2.38 × 101325

= 241153.5 Pa

Converting it into kPa we have the final answer as

<h3>241.15 kPa</h3>

Hope this helps you

8 0
3 years ago
When (R)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When
3241004551 [841]

Answer:

See explanation

Explanation:

The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.

On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.

7 0
3 years ago
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