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Alina [70]
3 years ago
14

Find the value of y log_4^64=y

Mathematics
1 answer:
Gekata [30.6K]3 years ago
6 0
4^3 = 64 so log_4(64) = 3 giving y = 3
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Can someone please help me with this (BTW ignore my writing)
Jobisdone [24]

ANSWER

On photo

EXPLANATION

Use the quadratic formula since the equation doesn't factorize not simplify by 3

5 0
3 years ago
The table shows the average weight of animals. How many more tons does a blue whale weigh than an African elephant? Explain how
AVprozaik [17]

Answer:

The African elephant weighs <u>111.5 tons</u> less than a blue whale.

Step-by-step explanation:

Given:

Animal                         Weight(pounds)

African Elephant            15,000

Blue Whale                   238,000

Now, to find the weight of how more tons does a blue whale weigh than an African elephant.

As given, 1 ton = 2,000 pounds.

So, to convert the weight from pound to tons by dividing:

African elephant =15000\div 2000=7.5\ tons.

Blue whale =238000\div 2000=119\ tons.

Now, to get the weight of how more tons is blue whale weigh than an African elephant we subtract:

Blue\ whale - African\ elephant

=119 tons-7.5tons

=111.5\ tons

Therefore, the African elephant weighs 111.5 tons less than a blue whale.

8 0
3 years ago
5/6 + 1/12 = ??<br><br> Simplify answer fully
AlladinOne [14]
5/6+1/12
=taking LCM we get 10+1/12
=11/12 is the answer..!!
5 0
3 years ago
Read 2 more answers
Which line has the same slope as the line passing through (- 4, -1) and (-1, 8)
Troyanec [42]

The slope is [ 8 - (-1) ] / [ -1 - (-4) ] = 9 / 3 = 3;

The line has the equation: y - 8 = 3( x + 1);

y - 8 = 3x + 3;

y = 3x + 11.

7 0
3 years ago
Enter the explicit rule for the sequence
Softa [21]
Let's take a look at the first few numbers in the sequence based on the given rule:

a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)

Inspecting this pattern it seems like the power \frac{1}{4} is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be \big(\frac{1}{4} \big)^{n-1}. We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

a_n=6\big( \frac{1}{4} \big)^{n-1}

Where a_n is the nth number in our sequence.
8 0
3 years ago
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