Since em waves are not conveyed by that of the vibration of electrons, they do not need a medium to travel. Electrical and magnetic fields, that could exist anywhere, oscillate, creating waves.
<h3>What do you mean by Electromagnetic waves?</h3>
The oscillations here between electrostatic potential and a magnetic field produce waves known as electromagnetic waves, or EM waves. In other words, magnetism fields oscillate to form electromagnetic (EM) waves.
<h3>Electromagnetic waves, where are they?</h3>
In contrast to wave propagation, electromagnetism waves can travel without a medium. This implies that microwaves can pass not only through stationary surfaces like air and rock but also through empty space.
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Answer:
1. NO and Br₂
2. 77
3. 8.8
Explanation:
Let's consider the following reaction.
2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)
The equilibrium constant for this reaction is:
![Kc_{1}=\frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]} =1.3 \times 10^{-2}](https://tex.z-dn.net/?f=Kc_%7B1%7D%3D%5Cfrac%7B%5BNOBr%5D%5E%7B2%7D%7D%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%20%3D1.3%20%5Ctimes%2010%5E%7B-2%7D)
1. At this temperature does the equilibrium favor NO and Br₂, or does it favor NOBr?
Since Kc₁ < 1, the reactants are favored, that is, NO and Br₂.
2. Calculate Kc for 2 NOBr(g) ⇄ 2 NO(g) + Br₂(g)
The equilibrium constant is:
![Kc_{2}=\frac{[NO]^{2}[Br_{2}]}{[NOBr]^{2}} =\frac{1}{Kc_{1}} =77](https://tex.z-dn.net/?f=Kc_%7B2%7D%3D%5Cfrac%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%7B%5BNOBr%5D%5E%7B2%7D%7D%20%3D%5Cfrac%7B1%7D%7BKc_%7B1%7D%7D%20%3D77)
3. Calculate Kc for NOBr(g) ⇄ NO(g) + 1/2 Br₂(g)
The equilibrium constant is:
![Kc_{3}=\frac{[NO][Br_{2}]^{1/2} }{[NOBr]} =\sqrt{\frac{[NO]^{2}[Br_{2}]}{[NOBr]^{2}}} =\sqrt{Kc_{2}} =8.8](https://tex.z-dn.net/?f=Kc_%7B3%7D%3D%5Cfrac%7B%5BNO%5D%5BBr_%7B2%7D%5D%5E%7B1%2F2%7D%20%7D%7B%5BNOBr%5D%7D%20%3D%5Csqrt%7B%5Cfrac%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%7B%5BNOBr%5D%5E%7B2%7D%7D%7D%20%3D%5Csqrt%7BKc_%7B2%7D%7D%20%3D8.8)
The mass of ore required is
21 700 t.
r = 750 cm
V =

=

= 1.767 × 10⁹ cm³
The density of lead is 11.34 g/cm³.
So mass of lead sphere = 1.767 × 10⁹ cm³ ×

= 2.004 ×10¹⁰ g
2.004 ×10¹⁰ g ×

= 2.004 × 10⁷ kg
2.004 × 10⁷ kg ×

= 2.004 × 10⁴ t
92.5% efficiency means 92.5 t Pb per 100 t of ore.
Mass of ore = 2.004 × 10⁴ t Pb ×

= 2.17 × 10⁴ t ore = 21 700 t ore
Answer:
The answer is c( to send signals to control the body)