Explanation:
After the electron configuration, the last shell of the beryllium atom has two electrons. In this case, both the valence and valence electrons of beryllium are 2. We know the details about this. The elements that have 1, 2, or 3 electrons in the last shell donate the electrons in the last shell during bond formation.
Answer:
The correct option es interphase
Explanation:
The interface is a stage of the cell division where a lot of energy is demanded, and it is the longest of the entire cycle.
This is because it is here where the duplication of the genetic load is generated, that is, of the chromosomes.
The chromosomes reach the cell poles and this is how a contraction begins to appear in the middle of the cell, it is essential to clarify that the interface not only requires energy but also occupies 95% of the cell division.
In order to balance reactions, the number of each element must be the same on the left and right side. If I have 3 of element X on one side, I must have 3 of element X on the other side. That being said:
Zn + Fe(NO3)2 —> ZnNO3 + Fe
I have two NO3 groups on the left, so I will add a coefficient of 2 in front of the compound which has an NO3 group on the right side.
Zn + Fe(NO3)2 —> 2ZnNO3 + Fe
Since I now have 2 Zn’s on the right, and only 1 on the left, I will add a coefficient of 2 in front of Zn on the left.
2Zn + Fe(NO3)2 —> 2ZnNO3 + Fe
Lets check:
Zn: 2 right, 2 left (correct)
Fe: 1 right, 1 left (correct)
NO3 groups: 2 right, 2 left
We have successfully balanced the equation. :)
There are four unpaired electrons in the
5d sublevel (subshell).
