Answer: B) exactly the same as the initial momentum.
Explanation:
An inelastic collision occurs when the elements that collide remain together after the collision, and althogh the kinetic energy is not conserved because is transformed into other kinds of energy (thermal energy, for example), the linear momentum does.
This means the initial momentum before the collision will be equal to the final momentum after the collision:
The friction force between the box and the incline if the box does not slide down the incline will be 0.577
The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are several kinds of friction: Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.
Given the box resting on the inclined plane above has a mass of 20kg and the The incline sits at a 30 degree angle
We have to find the friction force between the box and the incline if the box does not slide down the incline
Since the frictional force F₁ must equal or exceed gravitational force F₂ down the incline:
F₁ = F₂
μmgcosΘ = mgsinΘ
μ = (mgsinΘ)/(mgcosΘ)
μ = tanΘ
μ = 0.577
Hence the friction force between the box and the incline if the box does not slide down the incline will be 0.577
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Each point along the track of one solar mass star represents the star's surface temperature and luminosity at one time.
<h3>What is the one-solar mass star?</h3>
A star having a mass equal to the mass of the Sun is called a one-solar mass star.
Its life track shows the luminous intensity as well as the surface temperature.
Learn more about one-solar mass star.
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The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.
<h3>
Angular velocity of the tire</h3>
The angular velocity of the tire is the rate of change of angular displacement of the tire with time.
The magnitude of the angular velocity of the tire is calculated as follows;
ω = 2πN
where;
- N is the number of revolutions per second
ω = 2π x (5.25 / 3)
ω = 11 rad/s
<h3>Tangential velocity of the tire</h3>
The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.
The magnitude of the tangential velocity is caculated as follows;
v = ωr
where;
- r is the radius of the car's tire
v = 11r m/s
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The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.
HOW TO CALCULATE MASS:
- The mass of an object can be calculated by dividing the force applied to the object by its acceleration.
- According to this question, a bus can accelerate from rest to 15.5 m/s over 8.25s. The acceleration can be calculated as follows:
- The mass of the bus = 7500N ÷ 1.88m/s²
- The mass of the bus = 3989.4kg
- Therefore, the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.
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