3 years ago

The surface or material that underlies a two-dimensional work of art is called the ____.

Physics

1 answer:

Paul [167]3 years ago

5 0

The surface or material that underlies a two-dimensional work of art is called the support.

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What is the weight of an astronaut who has a mass of 90 kg on the moon? (Note: acceleration due to gravity of the moon is 1.62 N

motikmotik

Answer:

W = 145.8 [N]

Explanation:

To solve this problem we must remember that weight is defined as the product of mass by gravity, in this case lunar gravity.

W = m*g

where:

m = mass = 90 [kg]

g = gravity acceleration = 1.62 [kg/m²]

W = 90*1.62

W = 145.8 [N]

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3 years ago

The default unit of rotational speed is 'radians per second' or 'rad/s'. If a someone sits at the edge of a 5m radius carousel a

Blizzard [7]

The rotational speed of the person is 0.4 rad/s.

<h3>Rotational speed (rad/s)</h3>

The rotational speed of the person in radian per second is calculated as follows;

v = ωr

where;

v is linear speed in m/s
r is radius in meters
ω is speed in rad/s

ω = v/r

ω = 2/5

ω = 0.4 rad/s

Thus, the rotational speed of the person is 0.4 rad/s.

Learn more about rotational speed here: brainly.com/question/6860269

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2 years ago

Projectile motion is a combination of which two types of motion?

belka [17]

Vertical Free Fall and Constant Horizontal Motion

4 0

3 years ago

Read 2 more answers

What causes convection What causes convection currents, and what do they do? currents, and what do they do?

yaroslaw [1]

Answer:

it helps energy

Explanation:

to get electricity

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3 years ago

A college student is working on her physics homework in her dorm room. Her room contains a total of 6.0 X10^26 gas molecules. As

ipn [44]

Answer:

$\Delta T =11.904\ K$

Explanation:

given,

total gas molecule , N = 6 x 10²⁶

Power,P = 125 W

Δ t = 19 min = 19 x 60 s

Δ T = ?

Power,

$P = \dfrac{energy}{time}$

$E_n=P\times \Delta t$

$E_n=125\times 19\times 60$

$E_n=142500\ J$

we now,

$E_n = \dfrac{3}{2}Nk_b\Delta T$

$\Delta T = \dfrac{E_n}{\dfrac{3}{2}Nk_b}$

where as, k_b = 1.38 x 10⁻²³ J/K

$\Delta T = \dfrac{142500}{\dfrac{3}{2}\times 6 \times 10^{26}\times 1.38 \times 10^{-23}}$

$\Delta T =11.904\ K$

The increase in temperature is equal to $\Delta T =11.904\ K$

7 0

3 years ago