Answer:
A) ρ=
B) μ=
C) v=
D)e=
Explanation:
A)
The magnetic field can be find knowing the current is the charge per second
β= 
β= 8.75x10^{19}e*s
Electron density
ρ=
B)
μ= 
μ
C)
The drift speed using last information found
D)
To compared the random thermal motion and the current's drift speed
Answer:
The total mechanical energy of the skydiver is, E = 96402.6 J
Explanation:
Given data,
The mass of the skydiver, m = 100 kg
The speed of the skydiver at 80 m height, v = 60 m/s
The initial velocity of the skydiver, u = 0
Using the III equations of motion,
v² = u² + 2gs
s = v²/2g
Substituting the given values,
s = ½ 60²/ 9.8
= 18.37 m
Hence the initial total distance of the skydiver from the ground initially,
h = s + d
= 18.37 + 80
= 98.37 m
Since the total mechanical energy of a system is conserved, the total mechanical energy of the skydiver at height 'h' is equal to the total mechanical energy at height 'd'.
E = P.E + K.E
= mgh + ½ mu²
= 100 x 9.8 x 98.37 ( ∵ u = 0)
= 96402.6 J
Hence, the total mechanical energy of the skydiver is, E = 96402.6 J
a) 
, 
The work done by the student in each trial is equal to the gravitational potential energy gained by the student:
where
m = 68 kg is the mass of the student
g = 9.8 m/s^2 is the acceleration of gravity
is the gain in height of the student
For the first student, 
, so the work done is
The second student runs up to the same height (3.5 m), so the work done by the second student is the same:
2) 
, 
The power exerted by each student is given by
where
W is the work done
t is the time taken
For the first student, and 
, so the power exerted is
For the second student, 
and 
, so the power exerted is
