Answer: distance = 0.6 m
Explanation:
Given that:
Mass = 50g = 0.05kg
Ø = 25 degree
K = 25 N/m
Extension x = 0.1m
Let us first consider the total energy in the system.
Sum of the total energy = 0
That is
Final E - Initial E = 0
K.E, P.E and energy in the spring.
This equation will be reduced to
Mgh - 1/2mv^2 - 1/2Kx^2 = 0
Final velocity = 0 because of the spring energy
Initial height = 0
Final spring E = 0 as the spring returns to it normal length. Therefore,
Mgh - 1/2mv^2 - 1/2Kx^2 = 0
Since the ice cube was initially at rest, initial V = 0
Mgh = 1/2Kx^2
0.05 × 9.81 × h = 0.5 × 25 × 0.1^2
h = 0.125/0.4905
h = 0.255 m
how far will it travel up the slope before reversing direction?
Using SohCahToa for a right angle
SinØ = h/d
Where d = distance travel
Sin25 = 0.255/d
d = 0.255/sin 25
d = 0.603 m