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tatyana61 [14]
3 years ago
12

Calculate the number of moles in 3.01 x 10²² atoms of calcium.​

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
8 0

Answer:

Using dimensional analysis:

3.01x1022 molecules CO2 x 1 mol CO2/6.02x1023 molecules x 44. g CO2/mole = 2.20 g CO2

Explanation:

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Calculate the number of moles of NaOH contained in 250. mL of a 0.05M solution.
topjm [15]

Answer:

https://newshamchem.weebly.com/uploads/2/2/0/3/22035226/molarity_&_worksheet_answer.pdf

question 9.

Explanation:

3 0
3 years ago
Read 2 more answers
Oxygen is composed of three isotopes: oxygen-16, oxygen-17 and oxygen-18 and has an average atomic mass of 15.9982 amu. Oxygen-1
Irina-Kira [14]

Answer:

The percent abundance of oxygen-18 is 1.9066%.

Explanation:

The average atomic mass of oxygen is given by:

m_{O} = m_{^{16}O}*\%_{16} + m_{^{17}O}*\%_{17} + m_{^{18}O}*\%_{18}

Where:

m: is the atomic mass

%: is the percent abundance

Since the sum of the percent abundance of oxygen isotopes must be equal to 1, we have:  

1 = \%_{16} + \%_{17} + \%_{18}

1 = x + 3.2 \cdot 10^{-4} + \%_{18}

\%_{18} = 1 - x - 3.2 \cdot 10^{-4}

Hence, the percent abundance of O-18 is:  

m_{O} = m_{^{16}O}*\%_{16} + m_{^{17}O}*\%_{17} + m_{^{18}O}*\%_{18}  

15.9982 = 15.972*x + 16.988*3.2 \cdot 10^{-4} + 17.970*(1 - 3.2 \cdot 10^{-4} - x)

x = 0.980614 \times 100 = 98.0614 \%                                                              

Hence, the percent abundance of oxygen-18 is:

\%_{18} = (1 - 3.2 \cdot 10^{-4} - 0.980614) \times 100 = 1.9066 \%                      

Therefore, the percent abundance of oxygen-18 is 1.9066%.

I hope it helps you!                                                      

8 0
3 years ago
What is the molarity of a sodium chloride solution made by dissolving 4.512 moles to make 2.0 L?
Svet_ta [14]

Answer:

2.40 M

Explanation:

The molarity of a solution tells you how many moles of solute you get per liter of solution.

Notice that the problem provides you with the volume of the solution expressed in milliliters,

mL

. Right from the start, you should remember that you must convert this volume to liters by using the conversion factor

1 L

=

10

3

mL

Now, in order to get the number of moles of solute, you must use its molar mass. Now, molar masses are listed in grams per mol,

g mol

−

1

, which means that you're going to have to convert the mass of the sample from milligrams to grams

1 g

=

10

3

mg

Sodium chloride,

NaCl

, has a molar mass of

58.44 g mol

−

1

, which means that your sample will contain

unit conversion



280.0

mg

⋅

1

g

10

3

mg

⋅

molar mass



1 mole NaCl

58.44

g

=

0.004791 moles NaCl

This means that the molarity of the solution will be

c

=

n

solute

V

solution

c

=

0.004791 moles

2.00

⋅

10

−

3

L

=

2.40 M

The answer is rounded to three sig figs, the number of sig figs you have for the volume of the solution.

6 0
3 years ago
Order the elements from smallest to largest atomic number
postnew [5]

the largest is francium, Z=87 , or caesium, Z=55 ; and the smallest is definitely helium, Z=2 .

Explanation:

make me Brainliest

8 0
3 years ago
How many moles of Mg are present in 62.23 grams of Mg? (Show your calculations for full credit.)
mylen [45]
62.23 = 1512.5001499999998 moles
5 0
3 years ago
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