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Mnenie [13.5K]
3 years ago
9

Hot coffee with sugar (completely dissolved) is classified as?

Chemistry
1 answer:
attashe74 [19]3 years ago
5 0
Answer is solutions.

The definition of solutions is when you cannot see the different substances that make up solutions. One substance is DISSOLVED in the other, creating a homogeneous mixture.
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A sample of hydrogen gas will behave most like an ideal gas under the conditions of
elena55 [62]

Answer:

The Answer is gonna be C) high pressure and low temperature

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Determine the empirical formula of the following compound if a sample contains 5.28 gsn and 3.37 gf.
earnstyle [38]

Answer:

SnF2

Explanation:

you  divide by the smallest number which is 3.37

4 0
2 years ago
When the following redox equation is balanced with smallest whole number coefficients, the coefficient for nitrogen dioxide will
Phoenix [80]

In a redox reaction, electron could be lost or gained. The coefficients in the balanced redox reaction are;  1/2, 5, 1, 5, 2, 1.

<h3>What is a redox reaction equation?</h3>

A redox reaction equation shows the species that were oxidized or reduced in a redox reaction. In this case, we are asked for the coefficients in a balanced redox reaction equation.

We must recall that five electrons were lost/gained in the process hence the balanced reaction equation is;

1/2I2 + 5HNO3 -----> IO3^- + 5NO2 + 2H2O + H^+

The coefficients in the balanced equation therefore are; 1/2, 5, 1, 5, 2, 1.

Learn more about redox reaction: brainly.com/question/13293425

7 0
2 years ago
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What is the charge on an electron?
Llana [10]

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3 0
3 years ago
How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?
vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

Water ⇒ C = 1 cal/g°C

m = 65.8 g

Ti = 31.5°C

Tf = 36.9°C

Heat, Q = ?

2) Formula:

Q = mCΔT

3) Calculations:

Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

4) You can convert from calories to Joules using the conversion factor:

1 cal = 4.18 J

⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J

3 0
3 years ago
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