Helium decays to form lithium. 6 2 He → 6 3 Li + 0 -1 e This type of nuclear decay is called
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Answer:
Explanation:
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In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:
Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:
Thus, we solve for x as show below:
Therefore, the concentrations of both bromine and iodine are:
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Carbon dioxide, or 
, is a pure covalent bond.
pure - it's non-polar, because it's a linear & symmetrical bond.
covalent - covalence is when 2 electrons are shared by a pair of atoms. in the case of carbon dioxide, it's three atoms with an oxygen atom on the right, an oxygen atom on the left, and a carbon atom smack in the middle. 2 of carbon's extra electrons are shared with the right oxygen, and 2 other extra atoms are shared with with left oxygen.
pure - it's non-polar, because it's a linear & symmetrical bond.
covalent - covalence is when 2 electrons are shared by a pair of atoms. in the case of carbon dioxide, it's three atoms with an oxygen atom on the right, an oxygen atom on the left, and a carbon atom smack in the middle. 2 of carbon's extra electrons are shared with the right oxygen, and 2 other extra atoms are shared with with left oxygen.