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Amiraneli [1.4K]
3 years ago
9

Need help ASAP please and thank you

Physics
2 answers:
Sloan [31]3 years ago
4 0

Answer:

H

Explanation:

Akimi4 [234]3 years ago
4 0

Answer:

Pacific Ocean and Nazca plates is moving to west

Explanation:

beacause if they move to west they will move to the left

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__________ were initially developed to destroy the part of the brain that controls emotions.
sasho [114]

It’s Lobotomies on edg.

4 0
3 years ago
Read 2 more answers
An object with a momentum of 1500 kg-m/s directed east is acted upon by an impulse of 100.0 kg-m/s in the same direction. What i
fiasKO [112]

Answer:

The final momentum of the body = 1600 kgm/s

Thus the impulse that acted on the body. = 500 N.s

Explanation:

Momentum: This can be defined as the product of mass and velocity. The S.I unit of momentum is kgm/s. Momentum is a vector quantity.

Mathematically, momentum can be expressed as

M =mv.

Where M = momentum of the object, m = mass of the object, v = velocity of the object.

Impulse acting on the object = Final momentum of the object - initial momentum of the object

I = M₂ - M₁

M₂ = I + M₁......................... Equation 1

Where I = impulse, M₁ and M₂ = Final and initial momentum.

Note:

(i) The momentum and impulse act in the same direction

(ii) impulse is also a vector quantity.

Given: M₁= 1500 kgm/s, I = 100 kgm/s.

Substituting these values into equation 1

M₂ = 1500 + 100

M₂ = 1600 kgm/s.

Thus the final momentum of the body = 1600 kgm/s

14.

I = m(v-u)............................................... Equation 2.

Where I = impulse on the object, m = mass of the object, v = final velocity, u = initial velocity.

Given: m = 100 kg, v = 15 m/s, u = 10 m/s.

I = 100(15-10)

I = 100(5)

I = 500 N.s or 500 kgm/s.

Thus the impulse that acted on the body. = 500 N.s

7 0
4 years ago
What is the wavelength of a wave that travels at a speed of 3.0x10^8 m/s and has a frequency of 1.5x10^16 m/s?
Vlad [161]
Speed of wave = wavelength * frequency

Therefore, wavelength is 2.0 x 10^-8
5 0
3 years ago
A 76 N crate is hung from a spring
lutik1710 [3]

Answer: 0.169 (3 s.f.)

Explanation:

Force = 76 N

Spring constant = 450 N/m

Extension/displacement = x

Hooke's law states that: F = kx

Therefore, 76 = 450 X x

76/450 = x

0.169 (3 s.f.) = x

4 0
3 years ago
contractor will use a package emulsion having a specific gravity of 1.25 and relative bulk strength of 130 to open an excavation
tester [92]

Answer:

The burden distance is 7 ft

Solution:

As per the question:

Specific gravity of package emulsion, SG_{E} = 1.25

Specific gravity of diabase rock, SG_{R} = 2.76

Diameter of the packaged sticks, d = 3 in

Now,

To calculate the first trail shot burden distance, B:

B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d

B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22

B = 7 ft

5 0
3 years ago
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