Incident and reflective sound waves
Given:
Object in circular motion 25 m/s
1 second to go quarter circle
Required:
Centripetal acceleration:
Solution:
Acceleration = v2/r
Where v is the velocity and r is
the radian
Substituting the values into the
equation,
Acceleration = v2/r = (25
m/s)2/(4*pi/180) = 8952.47 m2/s2
False. What actually determines the properties of elements are the electrons, or aka valence electrons. They are used to bond, which determines its properties.
When object reached the terminal speed then its acceleration is zero
So as per Newton's II law we can say

now in that case we can say that net force is zero so here weight of the object is counter balanced by the drag force when it will reach at terminal speed
so we can write

so here we are given that





so terminal speed will be nearly 2 m/s
Reflection and refraction are two different phenomenons. In case of reflection, wave bounces back into the same medium after incident with the interface of two mediums. Reflection will happen if surface is shiny as well as smooth. If surface is irregular, one will get diffused reflection. Refraction means bending of light when waves travel from one medium to another