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OLga [1]
3 years ago
10

What mass of silicon dioxide contains 9.72 X10e24 molecules of silicon dioxide?

Chemistry
1 answer:
dangina [55]3 years ago
6 0

Answer:

1033.36g

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of SO2 also contains 6.02x10^23 molecules.

1 mole SO2 = 32 + (16x2) = 64g.

Now, If 64g of SO2 contains 6.02x10^23 molecules,

Therefore, Xg of SO2 will contain 9.72x10^24 i.e

Xg of SO2 = (64x9.72x10^24)/6.02x10^23

Xg of SO3 = 1033.36g.

Therefore, 1033.36g of SO2 contains 9.72x10^24 molecules

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Explanation:

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3 years ago
What is the pH when the hydrogen ion concentration is 1 x 10-3 M?
Fynjy0 [20]

Answer:

e. 3

Explanation:

In order to solve this problem we need to keep in mind the definition of pH:

  • pH = -log[H⁺]

As stated by the problem, the hydrogen ion concentration, [H⁺], is 1x10⁻³ M.

As all required information is available, we now can <u>calculate the pH</u>:

  • pH = -log(1x10⁻³ M)
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The correct option is thus e.

6 0
2 years ago
The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat
Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

 Half life of lipase t_{1/2} = 8 min x 60 s/min

                                       = 480 s

Rate constant for first order reaction is as follows.

         k_{d} = \frac{0.6932}{480}

                        = 1.44 \times 10^{-3}s^{-1}&#10;

Initial fat concentration S_{o} = 45 mol/m^{3}

                                                = 45 mmol/L

Rate of hydrolysis V_m_{o} = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = S_{o} (1 - X)

                                      = 45 (1 - 0.80)

                                      = 9 mol/m^{3}

or,                                  = 9 mmol/L

It is given that K_{m} = 5mmol/L

Therefore, time taken will be calculated as follows.

                    t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]

Now, putting the given values into the above formula as follows.

            t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]  

             = -\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s&#10;}{K_{M} ln (\frac{45 mmol/L&#10;}{9 mmol/L&#10;}) + (45 mmol/L - 9 mmol/L&#10;)]

              = 1642.83 s \times \frac{1 min}{60 sec}

              = 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0
3 years ago
Matter doesn't have to take up space as long as it has mass.
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Answer:

Matter always takes space (or has volume).

7 0
3 years ago
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Which atom would be expected to have a half-filled 6s subshell
eduard

Answer: I think the answer is Cesium (Cs)

Explanation:

A half-filled 6s subshell would be 6s^1

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3 years ago
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