Answer:
It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.
Explanation:
The question is not very much clear.
If you are asking for molecules then 1 mole water= 6.023 * 10^23
If you are asking for atoms then 1 mole water= 6.023 * 10^23 * 3
If you are asking for particles then,
So, in your example you would have one mole of water molecules. If you dissociated those water molecules, than you would end up with 2 moles of hydrogen atoms, and one mole of oxygen atoms.
I hope that was helpful!
H=1 proton,1 electron
O=8 protons,8 neutrons and 8 electrons
total particles in one H2O molecule-28
total no. of particles in 1 mole of water- 6.023 * 10^23 * 28
Answer:
c 43.38 g
Explanation:
The reaction between MnO2 and HCl can be represented by the following balanced equation:
MnO2 + HCl ---> Cl2 + MnCl2 + H2O
From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.
For the fact that HCl gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess, while the limiting reagent should be MnO2 .
Thus, the theoretical yield of Cl2 will be 60.25 g.
By definition, the percentage yield is given by
% Yield = (Actual Yield) / (Theoretical Yield),
This can be simplified to
Actual Yield = % Yield * Theoretical Yield
Plugging in the given values we have
Actual Yield = 72% * 60.25 = 43.38 g
