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USPshnik [31]
3 years ago
7

On a molar basis, which is a more effective bleaching agent- kbro3 or naocl?

Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
6 0
<span>On a molar a basis, the most effective bleaching agent kbro3 has more oxygen, but due to the bromine, it would make things look yellowish. The bromine would counteracts the bleaching effect. As we all know, bleach is naocl or hypochlorite</span>
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Hydrochloride acid +_________ zinc chloride +hydrogen​
Klio2033 [76]

Answer:

Hydrochloride acid + Zinc = Zinc Chloride + Hydrogen

Explanation:

When Hydrochloride acid and Zinc react, it results in the formation of Zinc chloride and hydrogen.

<em>Hope I helped</em>

3 0
2 years ago
Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

Squaring both sides, we get

(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}

Solve for <em>M</em>₂:

M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}

M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}

= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}

7 0
3 years ago
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Ulleksa [173]

Explanation:

As I_{2} is a covalent compound because it is made up by the combination of two non-metal atoms. Atomic number of an iodine atom is 53 and it contains 7 valence electrons as it belongs to group 17 of the periodic table.

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thus, we can conclude that london dispersion force is the major attractive force that exists among different I_{2} molecules in the solid.

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