M C C O R M I C K T E A M ’ S O P E N Q U A N T U M M AT E R I A L S D ATA B A S E
O F F E R S U N L I M I T E D A C C E S S T O
ANALYSES OF NEARLY 300,000 COMPOUNDS
Answer and Explanation:
We need to remember the formulas:
- pOH = -log[OH-]
- pH = -log[H+]
- pH + pOH = 14
When given the concentration of OH-, denoted as [OH-], we can plug that value into the equation pOH = -log[OH-] to find the pOH. Once we have found the pOH, we can then subtract that value from 14 to determine the value of pH.
Answer:
A) { + } Ge-Se { -}
B) { + } Ge-Br { - }
C) { - } Br-Se { + }
Explanation:
The (-)ive sign shall be placed for the atom with higher electronegativity, while the other atom will be electropositive.
a) Electronegativity of Ge = 2.01
Electronegativity of Se = 2.55
{ + } Ge-Se { -}
b) Electronegativity of Ge = 2.01
Electronegativity of Br = 2.95
{ + } Ge-Br { - }
c) Electronegativity of Br = 2.95
Electronegativity of Se = 2.55
{ - } Br-Se { + }
