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3 years ago

7

A total of 430 dogs and people attend a fundraising dog walk. Altogether, 1210 legs participated in the walk. How many dogs were

there?

1 answer:

meriva3 years ago

6 0

1210÷4=302.5 and u can have a half of a dog so there would be 302

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1 13/20 as a percentage

mrs_skeptik [129]

Answer: 565%

Step-by-step explanation: Convert fraction (ratio) 113 / 20 Answer: 565%

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3 years ago

The area of a rectangle is<br> 3/8 in and the length is 5/8 What is the width?

liberstina [14]

Answer:

The width W is :

$W=\frac{3}{5}$

Step-by-step explanation:

<em>Let A be the area of the rectangle </em>

<em>Let L be the length of the rectangle</em>

<em>Let W be the width of the rectangle </em>

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Formula:

A = L × W

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$\begin{aligned}A &=L \times W \\\Rightarrow W &=\frac{A}{L} \\\Rightarrow W &=\frac{\frac{3}{8}}{\frac{5}{8}} \\&=\frac{3}{8} \times \frac{8}{5} \\&=\frac{3 \times 8}{8 \times 5} \\&=\frac{3}{5}\end{aligned}$

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2 years ago

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Keith_Richards [23]

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4 0

3 years ago

If a monopolist supplies goods at a price; P = 170 - Q, with marginal cost; MC = 52. Find the quantity and price

Arada [10]

Answer:

Quantity = 59 units

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Step-by-step explanation:

The Demand function is given by

$P = 170 - Q$

The Marginal cost is given by

$MC = 52$

We are asked to find the quantity and price of goods.

Firstly, obtain the Marginal revenue function from the demand function

The Total revenue is given by

$TR = P \times Q \\\\TR = (170 - Q) \times Q \\\\TR = 170Q - Q^2$

The Marginal revenue is the derivative of the Total revenue,

$MR = \frac{d}{dQ} (TR) = 170Q - Q^2 \\\\MR = \frac{d}{dQ} (TR) = 170 - 2Q \\\\$

Assuming that the monopolist maximizes profits,

$MR = MC \\\\170 - 2Q = 52\\\\2Q = 170 - 52\\\\2Q = 118\\\\Q = 118/2\\\\Q = 59$

Therefore, the quantity is 59 units.

The price of each good is

$P = 170 - Q \\\\P = 170 - 59 \\\\P = 111$

Therefore, the price is $111.

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3 years ago

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finlep [7]

Answer:

<em>A. -3</em>

Step-by-step explanation:

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3 years ago

Read 2 more answers