Answer:
Minimum capacitance = 200 μF
Explanation:
From image B attached, we can calculate the current flowing through the capacitors.
Thus;
Since V=IR; I = V/R = 5/500 = 0.01 A
Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V
So minimum capacitance will be determined from;
i(t) = C(dv/dt)
So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]
C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF
Answer:
Recoil speed,
Explanation:
Given that,
Mass of the comet fragment,
Speed of the comet fragment,
Mass of Callisto,
The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,
V is recoil speed of Callisto immediately after the collision.
So, the recoil speed of Callisto immediately after the collision is
Answer:
The shortest possible stopping distance of the car is 175.319 meters.
Explanation:
In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:
(Eq. 1)
(Eq. 2)
After quick handling, we get that deceleration experimented by the car is equal to:
(Eq. 3)
Where:
- Deceleration of the car, measured in meters per square second.
- Kinetic coefficient of friction, dimensionless.
- Gravitational acceleration, measured in meters per square second.
If we know that and
, then deceleration of the car is:
The stopping distance of the car (), measured in meters, is determined from the following kinematic expression:
(Eq. 4)
Where:
- Initial speed of the car, measured in meters per second.
- Final speed of the car, measured in meters per second.
If we know that ,
and
, stopping distance of the car is:
The shortest possible stopping distance of the car is 175.319 meters.