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Arada [10]
3 years ago
14

A 17-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 33 N. Starting from rest, the sle

d attains a speed of 1.6 m/s in 9.8 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.
Physics
1 answer:
ycow [4]3 years ago
4 0

Answer:

\mu=0.185

Explanation:

From the question we are told that:

Mass m=17kg

Force F=33N

Velocity v=1.6m/s

Distance d= 9.8m

Generally the equation for Work done is mathematically given by

 W=\triangle K.E+\triangle P.E

Where

 \triangle K.E=(F-F_f)*2

 F_f=F+\frac{\triangle K.E}{d}

 F_f=33+\frac{0.5*17*1.6^2}{9.8}

 F_f=30.8N

Since

 f = \mu*m*g

 \mu= 30.8/(m*g)

 \mu= 30.8/(17*9.81)

 \mu=0.185

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Explanation:

Materials can be classified into three different types depending on their resistance:

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Therefore, the correct answer is:

B. It suddenly drops to zero

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Chiếu tia sáng lên một gương phẳng biết góc tới bằng 15⁰ hãy tính góc phản xạ bằng bao nhiêu
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3 years ago
If the coefficient of static friction is 0.357, and the same ladder makes a 58.0° angle with respect to the horizontal, how far
zavuch27 [327]

Answer: d= 0.57* l

Explanation:

We need to check that before ladder slips the length of ladder the painter can climb.

So we need to satisfy the equilibrium conditions.

So for ∑Fx=0, ∑Fy=0 and ∑M=0

We have,

At the base of ladder, two components N₁ acting vertical and f₁ acting horizontal

At the top of ladder, N₂ acting horizontal

And Between somewhere we have the weight of painter acting downward equal to= mg

So, we have N₁=mg

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So,

d=\frac{N2}{mg}*l * tan∅

Also, we have f₁=N₂

As f₁= чN₁

So f₁= 0.357 * 69.1 * 9.8

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Putting in d equation, we have

d= \frac{241.75}{69.1*9.8} *l * tan 58

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