Answer:
The difference in the decibel corresponses to a constant difference in the loudness perceived.
The refore the sound intensity from the orchestra is like 100 times that of the violin.
Explanation:
The frequency of the wave is determined as 7.96 Hz.
<h3>
Frequency of the wave</h3>
The frequency of the wave is calculated as follows;
y = A sin(ωt - kx)
where;
- A is amplitude of the wave
- ω is angular speed of the wave
ω = 2πf
f = ω/2π
f = (50)/(2π)
f = 7.96 Hz
Thus, the frequency of the wave is determined as 7.96 Hz.
Learn more about frequency of waves here: brainly.com/question/6297363
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Answer:
p2 = 9.8×10^4 Pa
Explanation:
Total pressure is constant and PT = P = 1/2×ρ×v^2
So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2
from continuity we have ρ×A1×v1 = ρ×A2×v2
v2 = v1×A1/A2
and
r2 = 2×r1
then:
A2 = 4×A1
so,
v2 = (v1)/4
then:
p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2
p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)
= 9.75×10^4 Pa
= 9.8×10^4 Pa
Therefore, the pressure in the wider section is 9.8×10^4 Pa
Answer:
Frequency of oscillation will increase
Explanation:
Because The period of a pendulum is inversely proportional to the square root of the gravitational acceleration, so as. Gravity increases on the moon period of oscillation decreases whereas period of oscillating pendulum is inversely proportional to frequency thus frequency is directly proportional to gravity so as gravity increases on the moon the frequency will increase
