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Brilliant_brown [7]
3 years ago
12

Find the percentage composition of each element in the compound having 9.8 grams of nitrogen,0.7 grams of hydrogen and 33.6 gram

s of oxygen
Chemistry
1 answer:
prisoha [69]3 years ago
4 0

Answer: The percentage composition of nitrogen , hydrogen and oxygen is 22.2 % , 1.59 % and 76.2% respectively.

Explanation:

Percentage composition is defined as the ratio of mass of substance to the total mass in terms of percentage.

Percentage composition=\frac{\text {mass of the element}}{\text {Total mass of the substance}}\times 100\%

a) {\text {percentage composition of nitrogen}}=\frac{\text {mass of nitrogen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of nitrogen}}=\frac{9.8g}{9.8+0.7+33.6}\times 100\%=22.2\%

b) {\text {percentage composition of hydrogen}}=\frac{\text {mass of hydrogen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of hydrogen}}=\frac{0.7}{9.8+0.7+33.6}\times 100\%=1.59\%

c) {\text {percentage composition of oxygen}}=\frac{\text {mass of oxygen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of oxygen}}=\frac{33.6}{9.8+0.7+33.6}\times 100\%=76.2\%

The percentage composition of nitrogen , hydrogen and oxygen is 22.2 % , 1.59 % and 76.2% respectively.

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The molecular formulas of the empirical ones of P₂O₅ and CH₂O are P₄O₁₀ and C₇H₁₄O₇, respectively, knowing that their molar masses are 310 and 200.18 g/mol, respectively.  

<h3>1. Molecular formula of P₂O₅</h3>

We can calculate the molecular formula as follows:

MF = n*EF   (1)

Where:

  • MF: is the molecular formula
  • EF: is the empirical formula
  • n: is an integer  

To calculate the integer <em>n</em>, we need to use the following equation:

n = \frac{M}{M_{EF}}   (2)

Where:

  • M: is the molar mass of P₂O₅ =  310 g/mol
  • M_{EF}: is the molar mass of the empirical formula

The molar mass of the empirical formula of P₂O₅  is given by:

M_{EF} = 2A_{P} + 5A_{O}

Where:

  • A_{P}: is the atomic weight of phosphorus = 30.974 g/mol
  • A_{O}: is the <em>atomic weight</em> of oxygen = 15.999 g/mol

So, the <em>molar mass</em> of the <em>empirical formula</em> of P₂O₅  is:

M_{EF} = (2*30.974 + 5*15.999) g/mol = 141.943 g/mol  

Now, we can find the integer <em>n </em>(eq 2).

n = \frac{M}{M_{EF}} = \frac{310 \:g/mol}{141.943 \:g/mol} = 2  

Finally, after multiplying the integer <em>n</em> by the number of atoms on the empirical formula of P₂O₅, we have (eq 1):

MF = n*EF = 2 \times P_{2}O_{5} = P_{(2 \times 2)}O_{(5 \times 2)} = P_{4}O_{10}

Therefore, the molecular mass of P₂O₅ is P₄O₁₀.

<h3>2. Molecular formula of CH₂O   </h3>

We know:

  • M: molar mass of CH₂O = 200.18 g/mol

To calculate the integer <em>n</em> and so the molecular mass of the molecule, we need to calculate the<em> molar mass</em> of the <em>empirical formula</em> of CH₂O.

M_{EF} = A_{C} + 2A_{H} + A_{O} = (12.011 + 2*1.008 + 15.999) g/mol = 30.026 \:g/mol

 

Now, the integer <em>n </em>is equal to (eq 2):

n = \frac{M}{M_{EF}} = \frac{200.18 g/mol}{30.026 g/mol} \approx 7

Finally, the molecular formula of the molecule is (eq 1):

MF = n*EF = 7 \times CH_{2}O = C_{(1 \times 7)}H_{(2 \times 7)}O_{(1 \times 7)} = C_{7}H_{14}O_{7}                              

Therefore, the molecular formula of CH₂O is C₇H₁₄O₇.

Learn more about molecular formula here:

  • brainly.com/question/1247523
  • brainly.com/question/14327882

I hope it helps you!

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