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3 years ago

Which statement best describes the polarity of SF 4 CI 2?

Chemistry

1 answer:

Tom [10]3 years ago

6 0

Answer:

use common sense!........

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When water decomposes into oxygen and hydrogen, the mass

Maurinko [17]

When water decomposes into oxygen and hydrogen, the mass "Remains Constant" as according to Law of Conservation of mass, mass can neither be created not destroyed,.

In short, Your Answer would be Option A

Hope this helps!

8 0

3 years ago

The cell membrane is a)semi permeable b)selectively permeable

likoan [24]

Answer:

A. Semi Permeable.

Explanation:

Cell membranes are semi permeable.

7 0

1 year ago

A solution is known to contain only one type of cation. Addition of Cl1- ion to the solution had no apparent effect, but additio

zhannawk [14.2K]

Answer:

We can have: Calcium, strontium, or barium

Explanation:

In this case, we have to remember the solubility rules for sulfate $SO_4~^-^2$ and the chloride $Cl^-$ :

Sulfate

All sulfate salts are SOLUBLE-EXCEPT those also containing: Calcium, silver, mercury (I), strontium, barium or lead.( $Ca^+^2~,Ag^+~,Hg_2^+^2~,Sr^+2~,Ba^+^2~,Pb^+^2$ ), which are NOT soluble.

Chloride

All chloride salts as SOLUBLE-EXCEPT those also containing: lead, silver, or mercury (I). ( $Pb^+^2~,Ag^+~,Hg_2~^+^2$ ), which are NOT soluble.

If we the salt formed a precipitated with the sulfate anion, we will have as possibilities "Calcium, silver, mercury (I), strontium, barium or lead". If We dont have any precipitated with the Chloride anion we can discard "Silver, mercury (I), lead" and our possibilities are:

"Calcium, strontium, or barium".

I hope it helps!

7 0

3 years ago

Describe the double circulation system of the human body

Alika [10]

Answer:

we have two loops in our body in which blood circulates. One is oxygenated, meaning oxygen rich, and the other is deoxygenated, which means it has little to no oxygen, but a lot of carbon dioxide.

4 0

3 years ago

What is the mass, in grams, of a sample of 6.98 × 1024 atoms of magnesium (Mg)?

monitta

N=6.98*10²⁴
Nₐ=6.022*10²³ mol⁻¹

n(Mg)=N/Nₐ

m(Mg)=n(Mg)M(Mg)=M(Mg)N/Nₐ

m(Mg)=24.3g/mol*6.98*10²⁴/(6.022*10²³mol⁻¹)=281.7 g

5 0

3 years ago