Answer:
Average atomic mass = 79.9035 amu.
The given element is bromine.
Explanation:
Given data:
Mass of 1st isotope = 78.9183 amu
Percent abundance of 1st isotope = 50.69%
Mass of 2nd isotope = 80.9163 amu
Percent abundance of 1st isotope = 49.31%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (50.69×78.9183 )+(49.31× 80.9163) /100
Average atomic mass = 4000.3686+ 3989.9828 / 100
Average atomic mass = 7990.3514 / 100
Average atomic mass = 79.9035 amu.
The given element is bromine.
Answer:
Animal cells have centrosomes (or a pair of centrioles), and lysosomes, whereas plant cells do not. Plant cells have a cell wall, chloroplasts, plasmodesmata, and plastids used for storage, and a large central vacuole, whereas animal cells do not.
Answer:
47.74 g
Explanation:
Given data:
Formula units of SrF₂ = 2.31 ×0²³
Mass of SrF₂ = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ formula units
2.31 ×0²³formula units × 1 mol / 6.022 × 10²³ formula units
0.38 mol
Mass of SrF₂:
Mass = number of moles × molar mass
Mass = 0.38 mol × 125.62 g/mol
Mass = 47.74 g