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Leto [7]
4 years ago
8

The cockroach Periplaneta americana can detect a static electric field of magnitude 8.50 kN/C using their long antennae. If the

excess static charge on a cockroach is modeled as point charges located at the end of each antenna, what magnitude of charge q would each antenna possess in order for each antennae to experience a force of magnitude 2.00 μN from the external electric field? Calculate q in units of nanocoulombs (nC) .
Physics
1 answer:
erica [24]4 years ago
4 0

Answer:

0.235 nC

Explanation:

Given:

  • E = the magnitude of electric field = 8.50\ kN/C =8.50\times 10^{3}\ N/C
  • F = the magnitude of electric force on each antenna = 2.00\ \mu N =2.00\times 10^{-6}\ N
  • q = The magnitude of charge on each antenna

Since the electric field is the electric force applied on a charged body of unit charge.

\therefore E = \dfrac{F}{q}\\\Rightarrow q =\dfrac{F}{E}\\\Rightarrow q =\dfrac{2.00\times 10^{-6}\ N}{8.50\times 10^{3}\ N/C}\\\Rightarrow q =0.235\times 10^{-9}\ C\\\Rightarrow q =0.235\ nC

Hence, the value of q is 0.235 nC.

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The electric field at the distance of 3.5 meters from an infinite wall of charges is 125 N/C. What is the magnitude of the elect
RideAnS [48]

Explanation:

It is given that,

Distance, r = 3.5 m

Electric field due to an infinite wall of charges, E = 125 N/C

We need to find the electric field 1.5 meters from the wall, r' = 1.5 m. Let it is equal to E'. For an infinite wall of charge the electric field is given by :

E=\dfrac{\lambda}{2\pi \epsilon_o r}

It is clear that the electric field is inversely proportional to the distance. So,

\dfrac{E}{E'}=\dfrac{r'}{r}

E'=\dfrac{Er}{r'}

E'=\dfrac{125\times 3.5}{1.5}  

E' = 291.67 N/C

So, the magnitude of the electric field 1.5 meters from the wall is 291.67 N/C. Hence, this is the required solution.

5 0
4 years ago
Suppose a two-level system is in a bath with temperature 247 K. The energy difference between the two states is 1.1 × 10-21 J. W
Alik [6]

Answer:

The probability of higher energy state is 0.4200.

Explanation:

Given that,

Temperature = 247 K

Energy difference between two states E_{2}-E_{1}=1.1\times10^{-21}\ J

We need to calculate the probability of higher energy state

Probability of E_{1}= e^{-\beta E_{1}}

Probability of E_{2}= e^{-\beta E_{2}}

The total probability is

e^{-\beta E_{1}}+e^{-\beta E_{1}}=1

Here, E₁ = lower energy state

E₂ = higher energy state

Put the value of E₁ in to the formula

e^{-\beta(E_{2}-1.1\times10^{-21})}+e^{-\beta E_{1}}=1

e^{-\beta E_{2}}(e^{\beta 1.1\times10^{-21}}+1)=1

e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{KT}}}

Here, \beta=\dfrac{1}{KT}

Put the value into the formula

e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{1.380\times10^{-23}\times247}}}

e^{\beta E_{2}}=0.4200

Hence, The probability of higher energy state is 0.4200.

4 0
3 years ago
Why can't speed ratio ever equal mechanical advantage?
OLga [1]
Efficiency of a simple machine is the ratio of mechanical advantage and speed ratio.

If mechanical advantage = speed ratio then efficiency = 1
Which is impossible for a practical machine due to presence of frictional force which wastes some energy and thus lowers the output
6 0
3 years ago
The interstellar clouds called molecular clouds are _________.
ira [324]

Answer:

nebulas and they are the cool clouds in which stars form

Explanation:

The stars are born by chance. Fragments of matter are gathered from the cool clouds of gas and dust that float in space, the so-called nebulas. These particles are added by gravitational attraction to form a large mass.

This conglomerate, due to the effect of gravity, contracts on itself and as a consequence increases in its center, density, pressure and heat. In this way, atoms move faster and collide with each other. Under these conditions, nuclear fusion reactions soon begin. When they start the star is born.

3 0
3 years ago
MARKING BRAINLIEST! The velocity of sound waves in air is 343 m/s, 1,007 m/s in helium and 267 m/s in carbon dioxide. Which one
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Answer:

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Explanation:

Since the units are the same, the value should only be considered.

6 0
3 years ago
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