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Ira Lisetskai [31]
1 year ago
12

A current is detected in a photoelectric effect experiment when an electrode is illuminated with green light. Will a current als

o be detected if that electrode is illuminated with blue light
Physics
1 answer:
AnnZ [28]1 year ago
8 0

Due to the photon's energy, which is higher in blue light than green. When you point to the right, you can see that blue light can produce bigger amounts of energy than green light now does. The current of blue light is, therefore, greater than that of green light. Wit, Gore predicts that we will have most of the color violet and the least of the color red. Violet has more energy, and as we descend, energy declines since blue have more energy.

What is the photoelectric effect and how did it change our concept of light and matter?

Heinrich Rudolf Hertz, a German physicist, developed the photoelectric phenomenon in 1887. Hertz discovered that when ultraviolet light shines on two metal electrodes with a voltage put across them, the light alters the voltage at which sparking occurs. This discovery is related to his work on radio waves.

What colors of light would cause the photoelectric effect?

The photoelectric effect refers to the finding that, under some circumstances, light striking a metal surface can result in the ejection of electrons. The light in the animation gains energy as it transitions from red to orange to yellow to green to blue.

Learn more about photoelectric effect: brainly.com/question/9260704

#SPJ4

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What does an electric circuit mean?​
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6 0
2 years ago
A 43.9-g piece of copper (CCu= 0.385 J/g°C) at 135.0°C is plunged into 254 g of water at 39.0°C. Assuming that no heat is lost t
Semmy [17]

Answer:

T = 40.501\,^{\textdegree}C

Explanation:

The interaction of the piece of copper and water means that the first one need to transfer heat in order to reach a thermal equilibrium with water. Then:

-Q_{out,Cu} = Q_{in,H_{2}O}

After a quick substitution, the expanded expression is:

-(43.9\,g)\cdot (0.385\,\frac{J}{g\cdot ^{\textdegree}C} )\cdot (T-135^{\textdegree}C) = (254\,g)\cdot (4.187\,\frac{J}{g\cdot ^{\textdegree}C} )\cdot (T-39\,^{\textdegree}C)

-16.902\,\frac{J}{^{\textdegree}C}\cdot (T-135^{\textdegree}C) = 1063.498\,\frac{J}{^{\textdegree}C} \cdot  (T-39^{\textdegree}C)

43758,192\,J = 1080.4\,\frac{J}{^{\textdegree}C}\cdot T

The final temperature of the system is:

T = 40.501\,^{\textdegree}C

8 0
2 years ago
Read 2 more answers
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