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raketka [301]
3 years ago
9

An upward force acts on a proton as it moves with a speed of 2.0 × 105 meters/second through a magnetic field of 8.5 × 10-2 tesl

a running from east to west. What is the force and direction of the force on the proton?
2.7 × 10-15 N to the north
2.7 × 10-15 N to the south
1.7 × 10-14 N to the north
1.7 × 10-14 N to the south
1.7 × 10-14 N downward
Chemistry
2 answers:
kotykmax [81]3 years ago
5 0
We are given:

<span>the speed of a proton = 2.0 × 10^5 meters/second; 
moving through a magnetic field = 8.5 × 10-2 tesla 
direction: east to west

The force and the direction of the force of the proton is determined using the magnetic field formula

F = qvxB

where q = charge 
v = vector
x = speed
B = magnetic field


F = 1.6x10^-19 C * </span>2.0 × 10^5 m/s * 8.5 × 10-^2 tesla
<span>
solve for F and the direction of your force is opposite the direction of the proton which is north since the proton is going upwards. 



</span><span>
</span>
mel-nik [20]3 years ago
3 0

Explanation :

It is given that,

Speed of the proton, v=2\times 10^{5}\ m/s

Magnetic field, B=8.5\times 10^{-2}\ T

Magnetic force is given by :

F=q(v\times B)

q is the charge of proton, q=1.6\times 10^{-19}\ C

So,

F=1.6\times 10^{-19}\ C\times 2\times 10^{5}\ m/s\times 8.5\times 10^{-2}\ T

F=2.72\times 10^{-15}\ N

The direction of force is given by using right hand rule. So, the force will act in upward direction.

Hence, the correct option is (a) " 2.72\times 10^{-15}\ N to the north".

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Answer:

58.9mL

Explanation:

Given parameters:

Initial volume  = 34.3mL    = 0.0343dm³

Initial concentration  = 1.72mM   = 1.72 x 10⁻³moldm⁻³

Final concentration  = 1.00mM = 1 x 10⁻³ moldm⁻³

Unknown:

Final volume  =?

Solution:

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   Therefore;

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where C and V are concentration and 1 and 2 are initial and final states.

        now input the variables;

                      1.72 x 10⁻³ x  0.0343 = 1 x 10⁻³  x V₂

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