All categories

3 years ago

What is the percent yield of either if 1.11L(d=0.7134 g/mL) is isolated from the reaction of 1.500L of C2H5OH

Chemistry

1 answer:

serg [7]3 years ago

6 0

Answer:

Percent yield of ether = 83.18%

Explanation:

Equation of the synthesis reaction of ether from ethanol is given as follows :

2 C₂H₅OH -----> C₂H₅OC₂H₅ + H₂0

Density = mass / volume

Therefore mass = density × volume

Density of ether = 0.7134 g/mL; volume of ether produced = 1.11 L = 1110 mL; Molar mass of ether = 74 g/mol

Mass of ether produced = 0.7134 g/mL × 1110 mL = 791.874 g

Density of ethanol = 0.789 g/mL; volume of ethanol = 1.50 L = 1500 mL; molar mass of ethanol = 46 g/mol

Mass of ethanol reacted = 0.789 g/mL × 1500 mL = 1183.5 g

From the equation of reaction, 2 mole of ethanol produces 1 mole of ether

Mass of 2 moles of ethanol = 2 × 46 = 92 g

Therefore, 92 g of ethanol produces 74 g of ether

1183.5 g of ethanol will produce 1183.5 × 74/92 grams of ether = 951.945 g of ether

Percent yield of ether = actual yield/theoretical yield × 100%

Actual yield of ether = 791.874 g; theoretical yield of ether = 951.945 g

Percent yield of ether = (791.874 g × 951.945 g) × 100 %

Percent yield of ether = 83.18%

You might be interested in

Consider the following system at equilibrium where H° = -87.9 kJ, and Kc = 83.3, at 500 K. PCl3(g) + Cl2(g) PCl5(g) When 0.17 mo

BigorU [14]

Answer:

K remains the same;

Q < K;

The reaction must run in the forward direction to reestablish the equilibrium;

The concentration of $PCl_3$ will decrease.

Explanation:

In this problem, we're adding an excess of a reactant, chlorine gas, to a system that is already at equilibrium. According to the principle of Le Chatelier, when a system at equilibrium is disturbed, the equilibrium shifts toward the side of the equilibrium that minimizes the disturbance.

Since we'll have an excess of chlorine, the system will try to reduce that excess by shifting the equilibrium to the right. Therefore, the reaction must run in the forward direction to reestablish the equilibrium.

The value of K remains the same, as it's only temperature-dependent, while the value of Q will be lower than K, that is, Q < K, as Q < K is the case when reaction proceeds to the right.

As a result, since $PCl_3$ is also a reactant, its concentration will decrease.

8 0

3 years ago

A sample of 5.72 g of liquid 1-propanol, C, H, O, is combustod with 43.4 g of oxygen gas, Carbon dioxide and water are

bekas [8.4K]

Answer:

2C3H8O + 9O2 ==> 6CO2 + 8H2O ... balanced equation

moles propanol = 5.26 g x 1 mol/60.1 g = 0.0875 moles

moles O2 = 31.8 g x 1 mol/31.9 g = 0.997 moles O2

Propanol is limiting based on the mol ratio in balance equation of 2 : 9

To find mass of O2 (excess reagent) left over, we will first find moles O2 used up.

moles O2 used = 0.0875 mol propanol x 9 mol O2/2 mol propanol = 0.394 moles O2 used

moles O2 left over = 0.997 mol - 0.394 mol = 0.603 mol O2 left

mass O2 left = 0.603 mol O2 x 32 g/mol = 19.3 g O2 left over

6 0

1 year ago

An alcohol is 58.80 % C and 9.889 % H by mass. The rest is oxygen. What is the empirical formula of the alcohol? Enter the eleme

PilotLPTM [1.2K]

Answer:

hco I believe

Explanation:

Pretty sure about this, when do you need to put it in?

6 0

3 years ago

According to the equation below, how many moles of PbO are required to generate 3.88×1023 nitrogen molecules?

saul85 [17]

Answer:

1.935 mole

Explanation:

We'll begin by calculating the number of mole present in 3.88x10^23 molecules of nitrogen(N2). This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. Therefore 1 mole of N2 contains 6.02x10^23 molecules.

Now if 1 mole of N2 contains 6.02x10^23 molecules,

Then Xmol of N2 will contain 3.88x10^23 molecules i.e

Xmol of N2 = (3.88x10^23)/6.02x10^23

Xmol of N2 = 0.645 mole

Now, we can obtain the number of moles of PbO required to generate 3.88x10^23 molecules (i.e 0.645 mole) of N2. This is illustrated below:

The equation for the reaction is given below:

3PbO + 2NH3 → 3Pb + N2 + 3H2O

From the balanced equation above, 3 moles of PbO produced 1 mole of N2.

Therefore, Xmol of PbO will produce 0.645 mole of N2 i.e

Xmol of PbO = 3 x 0.645

Xmol of PbO = 1.935 mole.

From the calculations made above,

1.935 mole of PbO will produce 3.88x10^23 molecules of nitrogen (N2).

8 0

3 years ago

What structure holds the sister chromatids to the spindle fibers?

olganol [36]

The answer is <span>a. kinetochore.

A kinetochore is a protein structure that holds the </span><span>sister chromatids to the spindle fibers. It is the place on chromatids where the spindle fibers bind during the cell division. As the result, sister chromatids are pulled apart to the opposite ends of the cell.</span>

8 0

3 years ago