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padilas [110]
2 years ago
8

Kevin travels from the United States to Australia for the winter, but when he gets there it feels more like summer. Which statem

ent explains this?
A) The Northern Hemisphere is experiencing an equinox.
B) The Southern Hemisphere is experiencing an equinox.
C) The Southern Hemisphere is tilted toward the sun, so it is summer in Australia.
D) The Southern Hemisphere is tilted away from the sun, so it is summer in Australia.
Chemistry
1 answer:
Karo-lina-s [1.5K]2 years ago
4 0

Answer:

The Northern Hemisphere is tilted away from the sun.

Explanation:

Kevin travels from the United States to Australia for the winter, but when he gets there it feels more like summer. Which statement explains this? The Northern Hemisphere is tilted away from the sun. When it is winter, the United States receives the least direct solar energy, as compared with the rest of the year.

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How to know how many valence electrons are in an element
Alenkinab [10]

Answer:

Hope it helped

Explanation:

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3 years ago
Can any one please help me to answers this question i don't get it. thank in advance.
alex41 [277]
First, lets balance the reaction equation:
4Fe + 3O₂ → 2Fe₂O₃
It is visible form the equation that 4 moles of Fe require 3 moles of O₂
Molar ratio Fe/O₂ = 4/3 = 1.33
Molar ratio O₂/Fe = 3/4 = 0.75
Now, we check the molar ratios present:
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3 years ago
Which statements regarding the Henderson-Hasselbalch equation are true? If the pH of the solution is known as is the pKa for the
Sonbull [250]

Answer:

1, 2, and 3 are true.

Explanation:

The Henderson-Hasselbalch equation is:

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

  • If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If you know pH and pka:

10^(pH-pka) = \frac{[A^-]}{[HA]}

The ratio will be: 10^(pH-pka)

  • At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

0 = log₁₀ \frac{[A^-]}{[HA]}

10^0 = \frac{[A^-]}{[HA]}

1 = \frac{[A^-]}{[HA]}

As ratio is 1,  [conjugate base] = [acid] in solution.

  • At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If pH >> pKa,  10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]

  • At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If pH << pKa,  10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]

I hope it helps!

6 0
3 years ago
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