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AnnyKZ [126]
2 years ago
6

Describe any evidence that a chemical reaction occurred when you added 6 m hcl to the solution of sodium acetylsalicylate, also

explain why the changes that you observed took place.

Chemistry
1 answer:
irina1246 [14]2 years ago
3 0

The evidence that a chemical reaction occurred is can be change in color , formation of a precipitate , Here in the case when 6 m HCl to the solution of sodium acetylsalicylate, the formation of precipitate that is of aspirin takes places that can be taken as a evidence that a reaction is occured. The reaction can be seen in the image attached.

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You would use the formula for Boyle's Law:

(P1) (V1) = (P2) (V2)

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2 years ago
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N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f
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Answer : The final concentration of N_2O_5 is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.89\times 10^{-3}\text{ min}^{-1}

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}

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Answer:

The answer will be listed below.

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Who was the first person to propose that atoms existed?
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Answer:

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d) Cupric bromide: CuBr₂, cuprous bromide: CuBr.

Explanation:

a) Ammonia is the neutral substance, which as molecular formula NH₃ when it gains a proton, it becomes the ammonium ion NH₄⁺.

b) In the name of salts, first, it comes the cation name, in this case, all the cations are the magnesium (Mg²⁺). The ions of sulfur can be oxidized or not, the termination "ide" indicates the non-oxidized ion (S⁻²), "ite" the less oxidized (SO₃⁻²), and "ate" the more oxidized (SO₄⁻²). To do the molecular formula, the charges are replaced without the signals and put down. If they are equal, the number is not put.

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cupric bromide: CuBr₂ (oxidation number = +2)

cuprous bromide: CuBr (oxidation number = +1)

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