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Lina20 [59]
3 years ago
8

The acceleration due to gravity on Earth is 9.80 m/s 2 . If the mass of a honeybee is 0.000100 kilograms, what is the weight of

this insect?
Chemistry
1 answer:
sweet [91]3 years ago
5 0
Okay so i think the answer to this is.

weight=mg

m=0.000100 g=9.80

so weight= 0.00980 kgm/s2
Hopefully thats correct (i am horrible at math) 
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Fill in the coefficients that will balance the following reaction:
vfiekz [6]

6NaC₂H₃O₂   +  Fe₂O₃   →   2Fe(C₂H₃O₂)₃  +  3Na₂O

Explanation:

Given equation;

      NaC₂H₃O₂   +  Fe₂O₃   →   Fe(C₂H₃O₂)₃  +  Na₂O

To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.

Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.

      aNaC₂H₃O₂   +  bFe₂O₃   →   cFe(C₂H₃O₂)₃  +  dNa₂O

a, b, c and d are the coefficients that  will balance the equation.

 conserving Na;    a  = 2d

                       C:     2a  = 6c

                       H:     3a  = 9c

                       O;      2a + 3b  = 6c + d

                       Fe:     2b = c

let a = 1

    solving:

      2a = 6c

       2(1) = 6c

          c = \frac{2}{6}  = \frac{1}{3}

      2b = c

          b = \frac{1}{2}  x \frac{1}{3} = \frac{1}{6}

     d = 2a + 3b - 6c = 2(1 ) + (3 x\frac{1}{6}  )  - (6  x  \frac{1}{3}) = \frac{1}{2}

Now multiply through by 6

  a = 6, b = 1, c = 2 and d = 3

             

                6NaC₂H₃O₂   +  Fe₂O₃   →   2Fe(C₂H₃O₂)₃  +  3Na₂O

learn more:

Balanced equation brainly.com/question/9325293

#learnwithBrainly

6 0
2 years ago
Can some one help I'm lost iam being timed:( Show using two conversion factors how you would convert from 0.020 kg into mg
dezoksy [38]

Answer:

20000 Mg

Explanation:

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BRAINLIESTT ASAP! PLEASE HELP ME :)<br><br> Compare stored mechanical energy and mechanical energy.
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Stored mechanical energy is energy stored and awaiting to be used and mechanical energy is the energy that was stored being used.

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c. x-rays

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