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nignag [31]
3 years ago
11

A balloon contains 2.0 L of air at 101.5 kPa. You squeeze the balloon to a volume of .75 L. What is the pressure of air on the i

nside of the balloon?
Chemistry
2 answers:
djverab [1.8K]3 years ago
5 0

Answer:

The answer is: P2 = 271kPa

Explanation:

Hello!

Let's solve this!

The data we have are:

P1: 101.5kPa

V1: 2L

V2: 0.75L

Q2 :?

P is pressure and V is volume.

In this case, we know that:

P1 * V1 = P2 * V2

We will clear P2 which is what we need to know:

P2 = P1 * V1 / * V2

P2 = (101.5kPa * 2L) /0.75L

P2 = 271kPa

We conclude that the answer is: P2 = 271kPa

Nataly_w [17]3 years ago
3 0

You would use the formula for Boyle's Law:

(P1) (V1) = (P2) (V2)

(101.5) (2.0) = (P2?) (.75)

*P2 = 270kPa (You're allowed 2 significant figures)

P = Pressure

V = Volume

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\qquad ☀️\pink{\bf{ {Answer  = \: \:   85.57g }}}

Molar mass of \bf Cu_2O

\qquad \twoheadrightarrow\sf 63.546 \times 2 +16

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\qquad \sf :\implies \dfrac{143.092 \times3.60×10^{23  }}{6.02×10^{23}}

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