How do you call a number of waves that pass a given point in a specific time, commonly one second.
1 answer:
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From my research, the image supports the question. From the graph given, we can construct the equation of the line using the two-point formula. Using the given value of 601 K, we can solve for the missing value of altitude.
y - y1 = [(y2 - y1)/(x2 - x1)](x- x1)
y - 147.52 = [ (567 - 147.54)/(78.11 - 18.4) ](x - 18.4)
Substituting y = 601 to solve for x:
601 - 147.52 = [ (567 - 147.54)/(78.11 - 18.4) ](x - 18.4<span>)
</span>x = 83
Therefore, the probe's instruments will fail at 83 kilometers.
y - y1 = [(y2 - y1)/(x2 - x1)](x- x1)
y - 147.52 = [ (567 - 147.54)/(78.11 - 18.4) ](x - 18.4)
Substituting y = 601 to solve for x:
601 - 147.52 = [ (567 - 147.54)/(78.11 - 18.4) ](x - 18.4<span>)
</span>x = 83
Therefore, the probe's instruments will fail at 83 kilometers.
Explanation:
Let us assume that the final resistance after stretching is . Since, the volume of rod does not change and the initial and final volume will be the same as follows.
V =
It is given that, .
Therefore,
We know that relation between resistance and area is as follows.
R =
=
= 9
= 9R
Thus, we can conclude that the resistance of the stretched wire is 9R.