Question

A bulb pile is driven to the ground with a 2.5 ton hammer. The drop height is 22 ft and the volume in last batch driven is 4 cu ft. Establish the safe load if the number of blows to drive the last batch is 36, volume of base and plug is 27 cu ft, and the soil K value is 28.

Answer 1

Answer:

The safe load is 159 ton

Explanation:

The safe load is equal to:

$L=\frac{WHBV^{2/3} }{K}$

Where:

W = weight of hammer = 2.5 ton

H = drop height = 22 ft

B = number of blows used to drive the last batch = 36/4 = 9 ft³

K = dimensionless constant = 28

V = uncompacted volume = 27 ft³

Replacing values:

$L=\frac{2.5*22*9*(27^{2/3}) }{28} =159ton$

Answer 2

Answer:

159.1 ton

Explanation:

The solution is shown in the attached file

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