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Brrunno [24]
3 years ago
14

A bulb pile is driven to the ground with a 2.5 ton hammer. The drop height is 22 ft and the volume in last batch driven is 4 cu

ft. Establish the safe load if the number of blows to drive the last batch is 36, volume of base and plug is 27 cu ft, and the soil K value is 28.
Physics
2 answers:
Olin [163]3 years ago
6 0

Answer:

The safe load is 159 ton

Explanation:

The safe load is equal to:

L=\frac{WHBV^{2/3} }{K}

Where:

W = weight of hammer = 2.5 ton

H = drop height = 22 ft

B = number of blows used to drive the last batch = 36/4 = 9 ft³

K = dimensionless constant = 28

V = uncompacted volume = 27 ft³

Replacing values:

L=\frac{2.5*22*9*(27^{2/3}) }{28} =159ton

Stels [109]3 years ago
5 0

Answer:

159.1 ton

Explanation:

The solution is shown in the attached file

Download docx
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