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Brrunno [24]
4 years ago
14

A bulb pile is driven to the ground with a 2.5 ton hammer. The drop height is 22 ft and the volume in last batch driven is 4 cu

ft. Establish the safe load if the number of blows to drive the last batch is 36, volume of base and plug is 27 cu ft, and the soil K value is 28.
Physics
2 answers:
Olin [163]4 years ago
6 0

Answer:

The safe load is 159 ton

Explanation:

The safe load is equal to:

L=\frac{WHBV^{2/3} }{K}

Where:

W = weight of hammer = 2.5 ton

H = drop height = 22 ft

B = number of blows used to drive the last batch = 36/4 = 9 ft³

K = dimensionless constant = 28

V = uncompacted volume = 27 ft³

Replacing values:

L=\frac{2.5*22*9*(27^{2/3}) }{28} =159ton

Stels [109]4 years ago
5 0

Answer:

159.1 ton

Explanation:

The solution is shown in the attached file

Download docx
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The images formed by convex mirrors are always in which form ​
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Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 gram
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Complete Question

Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?

A His results are accurate but not precise.

B His results are neither accurate nor precise.

C His results are both accurate and precise

D His results are precise but not accurate.

Answer:

Correct option is A

Explanation:

From the question we are told that  

   The  yield of the first test k  =  5.2 \  g

   The  yield of the second  is  u =  1.3 \  g

   The  third yield is  p =  8.5 \  g

   The  average yield  A = 5.0 \ g

    The  know yield is  A_S =  5.1 \  g

From the data given we see that

        A_S \ne A

Since his average yield is closer to the known yield then the answer is accurate

But since the yield for each test are not repeated the answer is not precise

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The length and width of a rectangular room are measured to be 3.92 ± 0.0035 m and 3.15 ± 0.0055 m. In this problem you can appro
Pavel [41]

Answer:

A)A=12.2480\ m^2

B)12.2480\pm 0.1029\ m^2

Explanation:

<u>Given:</u>

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Width of the room w= 3.15 ± 0.0055

A) Let A be the area of the room

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B)We will calculate uncertainty in each dimension

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The uncertainty in area will be sum of uncertainty in length and width

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%uncertainty in Area=0.0106

Uncertainty in Area=0.0106\times 12.2480=0.1029\ \rm m^2

There Area is12.2480 ± 0.1029\ \rm m^2

7 0
3 years ago
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