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daser333 [38]
4 years ago
7

How many electrons are available for bonding in oxygen

Physics
1 answer:
klasskru [66]4 years ago
3 0
8 electron are needed for bonding
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Which of the following ranching practices contributes to soil erosion?
Natasha2012 [34]

A. overgrazing of livestock

Explanation:

Overgrazing of livestock is the ranch practice that contributes to soil erosion.

Soil erosion is the washing away of the top layer of the earth on which plant grows.

  • Plants are covers of the earth and they prevent agents of denudation from actively washing away the soil.
  • When livestock are introduced into a place, continuous grazing leaves the surface bare.
  • The plants becomes depleted and the surface is exposed.
  • This fast tracks the process of overgrazing.

learn more:

Soil erosion brainly.com/question/2473244

#learnwithBrainly

6 0
3 years ago
A car travels at an average speed of 60km/h for 15 minutes. How far does the car travel in this time?
jok3333 [9.3K]

Answer:

In 15 minutes the car travels a distance of 15 km.

Explanation:

4 0
3 years ago
Read 2 more answers
Which tool is a wheel and axle?
Anton [14]
A steering wheel, a wrench, a screwdriver, and the back wheel of a bike are all examples of tools with a wheel and axle.
5 0
3 years ago
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The tilt of the Earth's axis of rotation changes from approximately 22.5° to 24.5° over a period of 41,000 years. This causes gl
kompoz [17]
<span>b. less climatic variation between the summer and winter seasons in the middle and high latitudes

As the tilt becomes higher (approaches 24 degrees) there is greater variation between the summer and winter months, due to the fact that the tilt toward the sun in the summer and away from the sun in the winter are more pronounced. </span>
3 0
3 years ago
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The small currents in axons corresponding to nerve impulses produce measurable magnetic fields. a typical axon carries a peak cu
Gemiola [76]

Answer:

6.66\cdot 10^{-12}T

Explanation:

The magnetic field produced by a current-carrying wire is given by

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0 is the vacuum permeability

I is the current

r is the distance from the wire

In this problem we have

I=0.040 \mu A=4\cdot 10^{-8}A

r = 1.2 mm = 0.0012 m

So the magnetic field strength is

B=\frac{(4\pi \cdot 10^{-7} H/m)(4\cdot 10^{-8}A)}{2\pi (0.0012 m)}=6.66\cdot 10^{-12}T

5 0
3 years ago
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