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4 years ago

Compare and contrast how observations and results can be used to support a conclusion to an experiment.

Physics

1 answer:

seropon [69]4 years ago

3 0

Answer:

Explanation:

Difference Between Observation and inference. Observation can be called as the process of gathering data and inference can be said to be a process of taking decisions about the gathered data. While Observation can be said to be a factual description, inference is an explanation to the collected data.

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The wavelengths corresponding to the harmonics of an organ pipe that is open at one end and closed at the other can be found by

Alecsey [184]

Answer:

The answer is "Option D"

Explanation:

Its ranges referring to the harmonic currents of its organ pipe which are open at one end and shut at another side could be noticed saying whether a strange amount of quarter-wavelengths should equal the length of its pipe. It's also the fourth wavelengths principle to have enough space and consume a minimum of 25% of our design frequency, as we're going to be taking 40 Hz.

3 0

3 years ago

There is a parallel plate capacitor. Both plates are 4x2 cm and are 10 cm apart. The top plate has surface charge density of 10C

liberstina [14]

Answer:

1) The total charge of the top plate is 0.008 C

b) The total charge of the bottom plate is -0.008 C

2) The electric field at the point exactly midway between the plates is 0

3) The electric field between plates is approximately 1.1294 × 10¹² N/C

4) The force on an electron in the middle of the two plates is approximately 1.807 × 10⁻⁷ N

Explanation:

The given parameters of the parallel plate capacitor are;

The dimensions of the plates = 4 × 2 cm

The distance between the plates = 10 cm

The surface charge density of the top plate, σ₁ = 10 C/m²

The surface charge density of the bottom plate, σ₂ = -10 C/m²

The surface area, A = 0.04 m × 0.02 m = 0.0008 m²

1) The total charge of the top plate, Q = σ₁ × A = 0.0008 m² × 10 C/m² = 0.008 C

b) The total charge of the bottom plate, Q = σ₂ × A = 0.0008 m² × -10 C/m² = -0.008 C

2) The electrical field at the point exactly midway between the plates is given as follows;

$V_{tot} = V_{q1} + V_{q2}$

$V_q = \dfrac{k \cdot q}{r}$

Therefore, we have;

The distance to the midpoint between the two plates = 10 cm/2 = 5 cm = 0.05 m

$V_{tot} = \dfrac{k \cdot q}{0.05} + \dfrac{k \cdot (-q)}{0.05} = \dfrac{k \cdot q}{0.05} - \dfrac{k \cdot q}{0.05} = 0$

The electric field at the point exactly midway between the plates, $V_{tot}$ = 0

3) The electric field, 'E', between plates is given as follows;

$E =\dfrac{\sigma }{\epsilon_0 } = \dfrac{10 \ C/m^2}{8.854 \times 10^{-12} \ C^2/(N\cdot m^2)} \approx 1.1294 \times 10^{12}\ N/C$

E ≈ 1.1294 × 10¹² N/C

The electric field between plates, E ≈ 1.1294 × 10¹² N/C

4) The force on an electron in the middle of the two plates

The charge on an electron, e = -1.6 × 10⁻¹⁹ C

The force on an electron in the middle of the two plates, $F_e$ = E × e

∴ $F_e$ = 1.1294 × 10¹² N/C × -1.6 × 10⁻¹⁹ C ≈ 1.807 × 10⁻⁷ N

The force on an electron in the middle of the two plates, $F_e$ ≈ 1.807 × 10⁻⁷ N

4 0

3 years ago

a body is thrown vertically upward from the earth's surface and it took 8 seconds to return to its original position . find out

Mnenie [13.5K]

Answer:

The initial velocity with which the body was thrown up is 39.2 m/s

Explanation:

The given parameters for the body are;

The time it takes the body to return back to its initial position = 8 seconds

To answer the question, we make use of the kinematic equation of motion, v = u - g·t

Where

v = The final velocity of the body = 0 m/s at the maximum height

u = The initial velocity

g = The acceleration due to gravity = 9.8 m/s²

t = The time in which the body spends in the air

Therefore, at maximum height, we have;

v = 0 = u - g·t

u = g·t

t = u/g

From h = 1/2gt², which gives t = √(2·h/g), the time the body takes to maximum height = The time the body takes to return to its original position from maximum height.

Therefore, the total time in which the body is in the air = 2 × t = 2× u/g

∴

The total time in which the body is in the air = The time it takes the body to return back to its initial position after being thrown = 2 × t = 8 seconds

∴ 2 × t = 8 s = 2 × u/g

8 s = 2 × u/g

u = (8 s × g)/2

∴ u = (8 s × 9.8 m/s²)/2 = 39.2 m/s

The initial velocity with which the body was thrown up = u = 39.2 m/s.

4 0

3 years ago

9. What is the acceleration of a boat if it starts from rest and then reaches a velocity of 24 m/s in 6.0 s?

Tom [10]

Answer:

b. 4 ms-2

Explanation:

acceleration = velocity / time

4 0

2 years ago

A 60.-kilogram physics student would weigh 1560

rosijanka [135]

Answer:

26m/s²

Explanation:

Given parameters:

Mass of the student = 60kg

Weight = 1560N

Unknown:

Acceleration due to gravity = ?

Solution:

Weight is a force on a body due to gravity;

Weight = mass x gravity

Insert the given parameters and solve;

1560 = 60 x gravity

Gravity = $\frac{1560}{60}$ = 26m/s²

4 0

3 years ago