Given :
One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in the y-direction.
To Find :
The velocity of the center of mass of these two particles.
Solution :
Speed of mass m, .
Speed of mass 2m , .
Speed of center of mass is given by :
Hence, this is the required solution.
Answer:
d=0.137 m ⇒13.7 cm
Explanation:
Given data
m (Mass)=3.0 kg
α(incline) =34°
Spring Constant (force constant)=120 N/m
d (distance)=?
Solution
F=mg
F=(3.0)(9.8)
F=29.4 N
As we also know that
Force parallel to the incline=FSinα
F=29.4×Sin(34)
F=16.44 N
d(distance)=F/Spring Constant
d(distance)=16.44/120
d(distance)=0.137 m ⇒13.7 cm
The answer of speed is 4.5m/s
Answer:
<u><em>Energy:</em></u> <em>It is the capacity of work done by the body, </em>
- <em>for example, kinetic energy, potential energy, thermal energy, and so on. The S.I. unit of energy is Joule.</em>
<u>Mechanical Energy: </u><em>Mechanical energy is the energy of the body corresponding to its motion or change in its position. </em>
- <em>For example, potential energy and kinetic energy.</em>
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<u><em>Law of conservation of energy: </em></u><em>According to the law of conservation of energy, the net energy of the system remains conserved.</em>
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- <em>For example, in the case of elastic collision, the net energy of the system is conserved before and after the collision.</em>
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<u><em>Law of conservation of energy for moving object: </em></u><em>The net energy of the moving object remains conserved.</em>
<em />
- <em>For example, the net energy of the ball sliding down the hill without any loss of energy remain conserved.</em>
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