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Evgen [1.6K]
3 years ago
13

6. Draw conclusions: Newton’s first law states that an object in motion will travel at a constant velocity unless acted upon by

an unbalanced force. How do these experiments show this?
Physics
2 answers:
Nitella [24]3 years ago
7 0
I’m not sure what experiments you’re referring to. Maybe if there is a Frictional force that stops and object from sliding after a period of time instead of it continuing to slide forever.
gavmur [86]3 years ago
5 0
You can test if it’s true by holding a pencil in mid air over a table and the table is supposed to be the unbalanced forced that stopped the pencil from moving at the constant velocity it was going by.
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A seagull flies at a velocity of 9.00 m/s straight into the wind.
RideAnS [48]

a)If it takes the bird 18.0 minutes to fly 6 km away from the earth, the wind's speed will be 4 m/s.

b) The bird would need 7 minutes and 42 seconds to fly back 6 kilometers if he turned around and flew with the wind.

c)Compared to the 133.33 seconds it would take without the wind, the overall round-trip time is affected by the wind.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

A seagull flies at a velocity,\rm v_{SA}  = 9 \ m/sec

The time the bird takes,t=18.0 min

The distance traveled relative to the earth = 6.00 km

a)

The seagull's relative velocity with reference to the ground as;

\rm v_{sg} = \frac{6.00 \times 10^3 \ m }{(20 min) \times \frac{60 s }{1 \ min}} \\\\ v_{sg}= 5.00 \ m/sec

Air velocity with reference to the ground is;

\rm v_{AG}= v_{SG}-v_{SA} \\\\ v_{AG} = 5.00 \ m/sec - 9.00 \ m/sec \\\\ v_{AG} = -4.00 \ m/sec

b)

If the bird turns around and flies with the wind, The time will he take to return 6.00 km is;

\rm v_{SG}=v_{SA}+v_{AG} \\\\ v_{SG}=-900 \ m/sec +(-4.00 \ m/sec) \\\\ v_{SG}= -13.00 \ m/sec

The time the bird takes;

\rm t = \frac{x_{SG}}{v_{SG}} \\\\ t = \frac{6.00 \times 10^3 \ m }{13.00 \ m/sec } \\\\ t = 462 m/sec \\\\ t = 7  \ min \  and  \ 42  \ sec

c)\

The total round-trip time compared to what it would be with no wind. is;

\rm  t = 20 \ min( \frac{60 \ sec }{1 \ min} )+ 462 \ sec \\\\ t = 1200 \ sec +6 462 \ ec \\\\ t= 1662 \ sec

The time for the round trip is;

\rm  t = \frac{12 \times 10^ 3 }{ 9 \ m/sec }  \\\\ t  = 1333.33 \ sec

Hence the wind's speed, the time bird would need to fly back the total round-trip time will be  4 m/s, 7 minutes and 42 seconds and 1333.33 sec.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

4 0
2 years ago
It takes a car traveling at 18 m/s, 240 seconds to reach Chick-Fil-A from the school. Determine how far Chick-Fil-A is from the
777dan777 [17]

Answer:

The requested distance is 4320 meters

Explanation:

We can use the formula for velocity in this movement at constant velocity (v), which is defined as the quotient between the distance covered divided the time it took:

v=\frac{distance}{time}

Since we know the velocity and the time, we can solve for the distance:

\neq v=\frac{distance}{time} \\18\,\frac{m}{s}  = \frac{distance}{240\,\,s} \\distance=18\,*\,240\,\,m\\distance= 4320\,\,m

8 0
3 years ago
As the pressure on a sample of gas increases, the volume of the sample _____. decreases stays the same increases
Allisa [31]
By Boyle's law the volume of the sample decreases, provided temperature is constant.
3 0
3 years ago
Read 2 more answers
Vocabulary Matching
Natasha_Volkova [10]

Answer:

instruments

Explanation:

5 0
3 years ago
How much power is generated by doing 500 j of work in 30 seconds
navik [9.2K]
Power is energy/time where energy is in joules and time is in seconds. The units for power is watts, W.

P = 500J/30s = 16.67 W

Hope this helps!
3 0
3 years ago
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