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Anastasy [175]
4 years ago
11

What causes thunder?

Physics
1 answer:
LUCKY_DIMON [66]4 years ago
4 0
I believe the answer is B.
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How would I use “Newton#1: Laws of Motion” in a sentence?
Anit [1.1K]

You would say "in Newtons !st law (state what it is) then continue on with the rest of your sentence! ;3

3 0
3 years ago
An iron bolt of mass 51.5 g hangs from a string 33.3 cm long. The top end of the string is fixed. Without touching it, a magnet
In-s [12.5K]

Answer:

Explanation:

Let magnetic force F acts towards right and the string makes an angle of θ with the vertical in equilibrium .Let T be tension in equilibrium

T cos θ = mg

T sin  θ = F

Dividing

Tan θ  = F / mg

F = mg Tanθ

= 51.5 x 9.8 x 10⁻³ x 26 / 20.8                        Tanθ = 26 / 20.8 )

=   630.875 X 10⁻³ N            

3 0
3 years ago
Radio waves and microwaves are similar because they both have
tekilochka [14]

The correct answer is

b. low frequencies and low energy.

In fact, microwaves and radio waves have frequency up to 10^{10}-10^{11} Hz, which are really low compared, for instance, to the frequency of gamma rays (10^{20} Hz). Moreover, the energy of an electromagnetic wave is directly proportional to its frequency:

E=hf

where h is the Planck constant and f the frequency; therefore, low frequency means also low energy.

4 0
3 years ago
The total volume of hydrogen gas needed to fill the hindenburg was 2.09 × 108 l at 1.00 atm and 25.1°
Inessa05 [86]
The solution for this problem:

PV = nRT 

But we are looking for n so, alter the original formula:
n = PV / RT

= (1.00 atm) x (2.09 x 10^8 L) / ((0.08205746 L atm/K mol) x  (25.1 + 273.15 K)) 

= 8539801.26 mol H2 
total volume = (8539801.26 mol H2) x (-286 kJ/mol H2) = -2.44 x 10^9 k J
3 0
3 years ago
Read 2 more answers
Oil at 150 C flows slowly through a long, thin-walled pipe of 30-mm inner diameter. The pipe is suspended in a room for which th
chubhunter [2.5K]

Answer:

<em>1.01 W/m</em>

Explanation:

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

From the above,<em> we assumed that the pipe wall and the oil are in thermal equilibrium</em>.

area of the pipe per unit length A = \pi r ^{2} = 7.069*10^{-4} m^2/m

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130 = <em>1.01 W/m</em>

4 0
4 years ago
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